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jeka94
3 years ago
5

What mass of compound must be weighed out to have a 0.0223 mol sample of H2C2O4 (M=90.04 g/mol)?

Chemistry
1 answer:
rodikova [14]3 years ago
5 0
Mass of  H2C2O4 :

mm = 90.04 g/mol

number of moles : 0.0223 moles

m = n * mm

m = 0.0223 * 90.04

m = 2.007 g 

hope this helps!.

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Data Given:
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Calculating Moles,
                                      n  =  m / M

                                      n  =  75.0 g / 44 g.mol⁻¹

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Putting Values in Eq. 1,

                    P  =  (1.704 mol × 0.08205 atm.L.mol⁻¹.K⁻¹ × 388 K) ÷ 3.0 L

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3 years ago
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Learn more about reactivity of metals at: brainly.com/question/28107797

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