Boyle’s law is P1V1 = P2V2. This shows that pressure and volume have an inverse relationship, so increase in pressure causes a decrease in volume. B is your answer
E=F*d/2 = k*d * d/2 =>
d^2= 2*E/k
d= sqrt(2*E/k)=sqrt(2*1J/1000N/m)=sqrt(20m^2)/100=0.045 m = 45 mm
It will land at 14139.19 m away.
Explanation:
The expression for range d on level ground is given by;
d=v² sin (2Ф) /g where Ф is the fire angle and g is acceleration due to gravity
Given v=400m/s ,Ф= 60° and g=9.8 so,
d= 400² sin(120°) /9.8
d=(400²×0.86602540378) / 9.8
d=14139.19 m
Motion for falling object : brainly.com/question/11799308
Keyword : initial velocity, angle, range
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Answer:
Archimedes principle: volume of water displaced by immersed object is equal to volume of water.
so if two object has same volume but different mass
then density determines the flotation of object,if an object has more density than water then it sinks.
I think this is called as special condition of floatation.
A. The magnitude of the spring force (in N) acting upon the object is 15.9 N
B. The magnitude of the object's acceleration (in m/s²) is 30.58 m/s²
C. The direction of the acceleration vector points toward the equilibrium position (i.e., to the left in the figure).
<h3>A. How to determine the force </h3>
- Extension (e) = 0.150 m
- Spring constant (K) = 106 N/m
- Force (F) = ?
F = Ke
F = 106 × 0.15
F = 15.9 N
<h3>B. How to determine the acceleration</h3>
- Mass (m) = 0.52 Kg
- Force (F) = 15. 9 N
- Acceleration (a) =?
F = ma
Divide both sides by m
a = F / m
a = 15.9 / 0.52
a = 30.58 m/s²
<h3>C. How to determine the direction of the acceleration vector</h3>
Considering the diagram, we can see that the spring was pulled away from the equilibrium point.
Thus, when the spring is released, it will move toward the equilibrium point. This is also true about the acceleration.
Therefore, we can conclude that the direction of the acceleration vector is towards the equilibrium point.
Learn more about spring constant:
brainly.com/question/9199238
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