Question

30.00 ml of a h2so4 solution with an unknown concentration was titrated to a phenolphthalein endpoint with 44.45 ml of a 0.1489 m naoh solution. what is the concentration of the h2so4 solution?

Answer 1

The concentration of the H2SO4 solution should be 0.1101 M.

Calculation of the concentration:

Since

Volume of H2SO4 = 30.00 mL = 0.030 L

Volume of NaOH= 44.45 mL = 0.04445 L

Concentration of NaOH= 0.1489 M

Now

The balanced equation is

H2SO4 + 2NaOH → Na2SO4 + 2H2O

Now the concentration of the H2SO4 solution is

b*Ca*Va = a*Cb*Vb

here,  b = the coefficient of NaOH = 2

Ca = ?

Va = the volume of H2SO4= 30.0 mL = 0.030 L

a = the coefficient of H2SO4 = 1

Cb = the concentration of NaOH = 0.1489 M

Vb = the volume of NaOH = 44.45 mL = 0.04445 L

Now

2*Ca*0.030 = 1* 0.1489* 0.04445

0.060 * Ca = 0.00661

Ca = 0.1101 M

Hence, The concentration of the H2SO4 solution is 0.1101 M.

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