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salantis [7]
1 year ago
11

How do I know if i’m doing number 2 right?

Physics
1 answer:
Ksju [112]1 year ago
8 0

We are given an object that is speeding up on a level ground.

Let's remember that the gravitational energy depends on the change in height, therefore, if the object is not changing its height it means that the gravitational energy remains constant.

The kinetic energy depends on the velocity. If the velocity is increasing this means that the kinetic energy is also increasing.

Now, every change in velocity requires acceleration and acceleration requires a force. The force and the distance that the object moves are equivalent to the work that is transferred to the object and therefore, the change in kinetic energy. This means that the total energy of the system increases as work is transferred to the mass.

We have that the total energy of the system increases in the form of kinetic energy and that the gravitational potential energy remains constant. Therefore, the diagrams should look like pie charts that grow but the area of the segment of the potential energy stays the same. It should look similar to the following.

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An atom of arsenic has how many electron-containing orbitals
irina [24]

Answer:

The Arsenic has three electron-containing orbitals. The orbitals s, p and d.

Explanation:

Arsenic is an element with an atomic number equal of 33, it means that it has 33 electrons in its orbitals in the following way:

1s^{2}

2s^{2}

2p^{6}

3s^{2}

3p^{6}

3d^{10}

4s^{2}

4p^{3}

Therefore, the Arsenic has three electron-containing orbitals (s, p d).

8 0
3 years ago
The valence electron occur in what part of the atom
Burka [1]
<span>The valence electrons occur in the outer shell of the atom. </span>
5 0
3 years ago
A small particle starts from rest from the origin of an xy-coordinate system and travels in the xy-plane. Its acceleration in th
CaHeK987 [17]

Answer:

The x-coordinate of the particle is 24 m.

Explanation:

In order to obtain the x-coordinate of the particle, you have to apply the equations for Two Dimension Motion

Xf=Xo+Voxt+0.5axt²(I)

Yf=Yo+Voyt+0.5ayt² (II)

Where Xo, Yo are the initial positions, Xf and Yf are the final positions, Vox and Voy are the initial velocities, ax and ay are the accerelations in x and y directions, t is the time.

The particle starts from rest from the origin, therefore:

Vox=Voy=0

Xo=Yo=0

Replacing Yf=12, Yo=0 and Voy=0 in (I) and solving for t:

12=0+(0)t+ 0.5(1.0)t²

12=0.5t²

Dividing by 0.5 and extracting thr squareroot both sides:

t=√12/0.5

t=√24 = 2√6

Replacing t=2√6, ax=2.0,Xo=0 and Vox=0 in (I) to obain the x-coordinate:

Xf=0+0t+0.5(2.0)(2√6)²

Xf= 24 m

5 0
3 years ago
A) Two workers are trying to move a heavy crate. One pushes onthe crate with a force A, which has amagnitude of 445 newtons and
Reptile [31]

Answer:

Divide then multiply or multiply then divide

Explanation:

to get the answer of a and b

3 0
2 years ago
Help again i need it quick
Romashka [77]

Answer:

it seems that the answer should be 7.5 mph as the average

Explanation:

sorry i did (s x t) when it was (s/t)

3 0
2 years ago
Read 2 more answers
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