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Xelga [282]
3 years ago
13

How does the sun's heat affect the humidity of a place​

Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
5 0

Answer:

the sun's heat affects humidity of how warm the air feels to us.

i tried

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A force that is doing work on a ball when that ball is falling through the air.
Ronch [10]

Answer:

i think the answer is gravity

3 0
2 years ago
Calculate the work done to push a 200-N object 5-meters
AVprozaik [17]
1000 joules
jskskmxk dnd
6 0
2 years ago
Aluminum and copper are good ____ because they don't have a strong hold on valence electrons. * a. Insulators b. Transistors c.
SOVA2 [1]

aluminum and copper are C.) conductors

6 0
3 years ago
Spaceship 1 and spaceship 2 have equal masses of 300 kg. spaceship 1 has a speed of 0 m/s, and spaceship 2 has a speed of 6 m/s.
Kipish [7]

The final speed is 3 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, in absence of external forces, the total momentum of the two spaceships must be conserved. So we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1 + m_2)v

where

m_1 = m_2 = 300 kg is the mass of each spaceship

u_1 = 0 m/s is the initial velocity of spaceship 1

u_2 = 6 m/s is the initial velocity of spaceship 2

v is the combined velocity of the two spaceships after the collision

Solving for v, we find

v=\frac{m_2 u_2}{m_1+m_2}=\frac{(300)(6)}{300+300}=3 m/s

So, their final speed is 3 m/s.

Learn more about conservation of momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

6 0
3 years ago
An 18g bullet is shot vertically into a 10kg block. The block lifts upward 9mm. The bullet penetrates the block in a time interv
stealth61 [152]

Answer:

The initial kinetic energy of the bullet is closest to 491.87 J

Explanation:

Given;

mass of bullet, m₁ = 18g = 0.018kg

mass of block, m₂ = 10kg

height moved by the block, h = 9 mm = 0.009 m

time taken for the bullet to travel through the block, t = 0.001s

let the initial velocity of the bullet = v₁

let the final velocity of the bullet = v₂

Apply the principle of conservation of linear momentum;

initial momentum = final momentum

0.018v₁ = v₂(0.018 + 10)

0.018v₁ = 10.018v₂ -----equation (1)

Apply the law of conservation of energy when the bullet lifts the block through 9mm

mgh = ¹/₂mv₂²

gh = ¹/₂v₂²

v₂² = 2gh

v₂ = √2gh

v₂ = √(2 x 9.8 x 0.009)

v₂ = 0.42 m/s

Substitute in v₂ in equation 1, to determine the initial velocity of the bullet;

0.018v₁ = 10.018v₂

0.018v₁  =  10.018(0.42)

0.018v₁  = 4.208

v₁ = 4.208 / 0.018

v₁ = 233.78 m/s

Now, determine the initial kinetic energy of the bullet;

K.E₁ = ¹/₂m₁v₁²

K.E₁ = ¹/₂(0.018)(233.78)²

K.E₁ = 491.87 J

Therefore, the initial kinetic energy of the bullet is closest to 491.87 J

6 0
3 years ago
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