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4 years ago

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The main goal of science is to A. Learn how to use the laws of nature to benefit humans. B. Learn about the universe and the law

s of nature. C. Replace old theories with new, more interesting theories. D. Develop new inventions and processes.

1 answer:

marishachu [46]4 years ago

7 0

The main goal of science is to learn about the universe and the laws of nature. <em>(B)</em>

The goal of Applied Science, Technology, and Engineering is to develop new inventions and processes (D), that can use the laws of nature to benefit humans. (A)

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Why do antoms move at different speeds depending pn weather they are in liqids or solids?

Salsk061 [2.6K]

Liquid matter has atoms that move moderately freely; this is shown that whenever you pour water into a cup, it fills the shape.
Solids on the other hand, have atoms that basically don't move; thus is because the item is purely compact, and, for contrast, putting a rock in a cup wouldn't fill the shape of the cup, it would just lie there as it's original form.

Hope this helps!

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4 years ago

A car travels from A to B at a speed of 40 mph then returns, using the same road, from B to A at a speed of 60 mph. What is the

bezimeni [28]

<h2>Average speed of round trip is 48 mph</h2>

Explanation:

Let the distance from A to B be s.

A car travels from A to B at a speed of 40 mph then returns, using the same road, from B to A at a speed of 60 mph.

$\texttt{Time taken to travel from A to B = }\frac{s}{40}\\\\\texttt{Time taken to travel from B to A = }\frac{s}{60}\\\\\texttt{Total time = }\frac{s}{40}+\frac{s}{60}\\\\\texttt{Total time = }\frac{60s+40s}{40\times 60}\\\\\texttt{Total time = }\frac{100s}{2400}\\\\\texttt{Total time = }\frac{s}{24}$

Total distance traveled = 2s

Total distance traveled = Average speed x Total time

$2s=\texttt{Average speed}\times \frac{s}{24}\\\\\texttt{Average speed = }48mph$

Average speed of round trip is 48 mph

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4 years ago

Identify which gas had the greatest volume change.

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Water and h20 delivery have been a very meaningful company to the community

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4 years ago

The density of air at room temperature is about 1.2 g/L. This is the same as

Verdich [7]

The correct answer is
<span>C) 1200 g/m3.

Let's see why. The relationship between liters and cube decimeters is
</span> $1 L = 1 dm^3$
Therefore,
$1 g/L= 1 g/dm^3$
However, we also know that
$1 dm^3 = 10^{-3} m^3$
Therefore,
$1 L = 10^{-3} m^3$
and
$1 \frac{g}{L}= 1 \frac{g}{10^{-3} m^3} =1 \cdot 10^3 \frac{g}{m^3} =1000 \frac{g}{m^3}$

Therefore, the density of the problem $1.2 g/L$ becomes
$d=1.2 g/L=1200 g/m^3$

3 0

3 years ago

A constant electric field with magnitude 1.50 ✕ 103 N/C is pointing in the positive x-direction. An electron is fired from x = −

romanna [79]

Answer:

The speed of electron is $1.5\times10^{7}\ m/s$

Explanation:

Given that,

Electric field $E=1.50\times10^{3}\ N/C$

Distance = -0.0200

The electron's speed has fallen by half when it reaches x = 0.190 m.

Potential energy $P.E=5.04\times10^{-17}\ J$

Change in potential energy $\Delta P.E=-9.60\times10^{-17}\ J$ as it goes x = 0.190 m to x = -0.210 m

We need to calculate the work done by the electric field

Using formula of work done

$W=-eE\Delta x$

Put the value into the formula

$W=-1.6\times10^{-19}\times1.50\times10^{3}\times(0.190-(-0.0200))$

$W=-5.04\times10^{-17}\ J$

We need to calculate the initial velocity

Using change in kinetic energy,

$\Delta K.E = \dfrac{1}{2}m(\dfrac{v}{2})^2+\dfrac{1}{2}mv^2$

$\Delta K.E=\dfrac{-3mv^2}{8}$

Now, using work energy theorem

$\Delta K.E=W$

$\Delta K.E=\Delta U$

So, $\Delta U=W$

Put the value in the equation

$\dfrac{-3mv^2}{8}=-5.04\times10^{-17}$

$v^2=\dfrac{8\times(5.04\times10^{-17})}{3m}$

Put the value of m

$v=\sqrt{\dfrac{8\times(5.04\times10^{-17})}{3\times9.1\times10^{-31}}}$

$v=1.21\times10^{7}\ m/s$

We need to calculate the change in potential energy

Using given potential energy

$\Delta U=-9.60\times10^{-17}-(-5.04\times10^{-17})$

$\Delta U=-4.56\times10^{-17}\ J$

We need to calculate the speed of electron

Using change in energy

$\Delta U=-W=-\Delta K.E$

$\Delta K.E=\Delta U$

$\dfrac{1}{2}m(v_{f}^2-v_{i}^2)=4.56\times10^{-17}$

Put the value into the formula

$v_{f}=\sqrt{\dfrac{2\times4.56\times10^{-17}}{9.1\times10^{-31}}+(1.21\times10^{7})^2}$

$v_{f}=1.5\times10^{7}\ m/s$

Hence, The speed of electron is $1.5\times10^{7}\ m/s$

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3 years ago