All categories

4 years ago

What do astronomers mean by light pollution?

Physics

2 answers:

Margarita [4]4 years ago

8 0

Answer:

a. Light pollution refers to light used for human activities that brightens the sky and hinders astronomical observations.

Explanation:

Light pollution is due to the excessive and misdirected use of artificial light. Light bulbs are often design in an incorrect way, since a great part of its light is not completely directed to the ground and an important percentage is emitted to the sky in where will be scattered and reflected back to ground by the particles in the atmosphere. That brings as an effect a sky glow, therefore the visibility of astronomical objects will be extremely reduce.

Hence, professional astronomical research and amateur observations will be affected. Light pollution has a negative impact on bird migration at night and in the health of difference species, humans also.

Triss [41]4 years ago

8 0

Answer:

Explanation:

<em>Letting you Know That The Answer Was Wrong LYK AKA Letting You Know :)</em>

You might be interested in

this Punnett square shows the cross between two pants. One parent has round seeds (RR). And the other parent has wrinkled seeds

Bad White [126]

All Offsprings will be round because it comes out as dominant evrytime and it has 0 ressesives. Hope this helped ;)

4 0

3 years ago

On Friday, September 28, 2018, Palu, Indonesia, on the island of Sulawesi, experienced an earthquake that generated a tsunami. F

Naily [24]

Answer: Proximity to active volcanoes

Explanation:

When volcanoes erupt, they can generate tsunamis in the following ways:

-Parts of the volcano (some of them may be underwater) could collapse, generating a big displacement of water and resulting in a tsunami.

-The magma chamber could also collapse as it empties, also generating water displacement.

-If the volcanoes are near to the shore, debris resulting from the eruption could hit the water at fast speeds, producing big waves and eventually a tsunami.

In this case, the proximity of Palu city to active volcanoes, especially ones that are so close to the shore, increases the risk of a tsunami.

7 0

3 years ago

A magnetic field is applied to a freely floating uniform iron sphere with radius R = 2.00 mm. The sphere initially had no net ma

grigory [225]

Answer:

$\omega=4.2704*10^-^5 rad/s$

Explanation:

Angular Momentum Formula For atoms= $L_{atom}=0.12Nm_{s}h$

Where:

m_{s}h is the momentum for one atom (m_s is the spin quantum number)

N is the number of atoms= $\frac{N_{A}*m}{M}$

Where:

N_A is Avogadro Number

m is the mass of sphere

M is the molar mass of iron

Angular Momentum Formula For atoms will be= $L_{atom}=0.12\frac{N_{A}m}{M} m_{s}h$

Angular Momentum of Sphere= $L_{sphere}=I\omega$

where:

$I=\frac{2mR^{2}}{5}$

So,Angular Momentum of Sphere= $L_{sphere}=\frac{2mR^{2}}{5}\omega$

Angular Momentum of sphere=Angular Momentum of atoms

$L_{sphere}$ = $L_{atom}$

$\frac{2mR^{2}}{5}\omega$ = $0.12\frac{N_{A}m}{M} m_{s}h$

For iron, $m_s =\frac{1}{2}$ . So above equation will become:

$\omega=\frac{0.12*5*N_{A}h}{4*M*R^{2} }$

Where R=2mm, M=0.0558Kg/mol (Molar Mass of iron),h=Planck's Constant/2π

$\omega=\frac{0.12*5*(6.022*10^{23})(6.63*10^{-34}/2*\pi)}{4*0.0558*(2*10^{-3})^{2}}$

$\omega=4.2704*10^-^5 rad/s$

5 0

3 years ago

A 5.00 kg rock whose density is 4300 kg/m3 is suspended by a string such that half of the rock's volume is under water. You may

12345 [234]

Answer:

The tension on the string is $T = 43.302 \ N$

Explanation:

From the question we are told that

The mass of the rock is $m_r = 5.00 \ kg = 5000 \ g$

The density of the rock is $\rho = 4300 \ kg/m^3 = 4.3 g/dm^3$

Generally the volume of the rock is mathematically evaluated as

$V = \frac{m_r}{\rho}$

substituting values

$V = \frac{5000}{4.3}$

$V = 1162.7 \ dm^3$

The volume of the rock immersed in water is

$V_w = \frac{V}{2}$

substituting values

$V_w = \frac{1162.7 }{2}$

$V_w = 581.4 \ dm^3$

mass of water been displaced by the this volume is

$m_w = V_w$ According to Archimedes principle

=> $m_w = 581.4 \ g$

$m_w = 0.5814 \ kg$

The weight of the water displace is

$W _w = m_w * g$

$W _w = 0.5814 * 9.8$

$W _w = 5.698 \ N$

The actual weight of the rock is

$W_r = m_r * g$

$W_r = 5.0 * 9.8$

$W_r = 49.0 \ N$

The tension on the string is

$T = W_r - W_w$

substituting values

$T = 49.0 - 5.698$

$T = 43.302 \ N$

4 0

3 years ago

How do you calculate the magnitude of the resultant force of two

zlopas [31]

Answer:

Two forces that act in opposite directions produce a resultant force that is smaller than either individual force. To find the resultant force subtract the magnitude of the smaller force from the magnitude of the larger force. The direction of the resultant force is in the same direction as the larger force.

3 0

3 years ago

Read 2 more answers