Question

Serenity has 58 m of fencing to build a four-sided fence around a rectangular plot of land. The area of the land is 210 square meters. Solve for the dimensions (length and width) of the field.

Answer 1

The dimensions of the rectangular( length and width) are 14m and 15m.

Here we have to find the dimension of the length and width.

Data given:

Fencing = 58m

Area = 210 m²

Let us assume the length be x

By this, we get the width as:

width = 58 - 2x / 2

         = 29-x

As the area is 210 m²

The formula to find the area of the rectangular is:

Area = length ×width

210 = x ( 29 -x)

x² - 29 x + 210 = 0

Formula to find the value of x from the quadratic equation:

x = -b ±$\sqrt{b^{2} - 4ac }$

For the general equation ax² + bx + c =0

As the equation is:

x² - 29x + 210 = 0

a = -1

b = -29

c = -210

So,

x = 29 ±$\sqrt{(29)^{2} - 4(-1)(-210) }$ / 2(-1)

  = 29± 1/-2

  = 14, 15

29 - x = 15, 14 (for the value of x = 14 and 15 respectively)

Therefore the dimensions are 14m and 15m.

To know more about the rectangular refer to the link given below:

brainly.com/question/25292087

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