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3 years ago

Define dynamic chemical equilibrium in terms of quantities of reactants and products

1 answer:

3 0

Dynamic chemical equilibrium is the point at which the rate of the forward reaction is equal to the rate of the reverse reaction.This means that reactants are converted to products and products are converted to reactants at an equal and constant rate.At this point the opposite rates are equal, not the concentrations. In terms of concentration, the concentration of reactants and products stabilizes at a fixed ratio.

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One way to represent this equilibrium is: 2 Al(s) 3 Br2(l)2 AlBr3(s) We could also write this reaction three other ways, listed

myrzilka [38]

The question is incomplete, the complete question is;

Aluminum metal and bromine liquid (red) react violently to make aluminum bromide (white powder). One way to represent this equilibrium is:

Al(s) + 3/2 Br2(l)AlBr3(s)

We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.

1) 2 AlBr3(s) 2 Al(s) + 3 Br2(l)

2) 2 Al(s) + 3 Br2(l) 2 AlBr3(s)

3) AlBr3(s) Al(s) + 3/2 Br2(l)

Answer:

See explanation

Explanation:

We have that; Al(s) + 3/2 Br2(l)AlBr3(s)

So;

Al(s) + 3/2 Br₂(l) = AlBr₃(s)

K = [ AlBr₃] / [ Al] [ Br₂]³/²

K² = [ AlBr₃]² / [ Al ] ² [ Br₂]³

Now;

1) 2 AlBr₃ = 2 Al(s) + 3 Br₂(l) =

K₁ = [ Al ] ² [ Br₂]³ / [ AlBr₃]²

K₁ = ( 1 / K² ) = K⁻²

For the second reaction;

2 ) 2 Al(s) + 3 Br₂(l) = 2 AlBr₃(s)

K₂ = [ AlBr₃ ]² / [ Al ]² [ Br₂ ]³

K₂ = K²

For the third reaction;

3 )

AlBr₃(s) = Al(s) + 3/2 Br₂(l)

K₃ = [ Al ] [ Br₂ ] ³/² / [ AlBr₃ ]

= ( 1 / K ) = K⁻¹

7 0

3 years ago

Is it possible for two different compounds to be made from the exact same two elements? Why or why not? With a limited number of

mario62 [17]

Yes, it is possible to combine the same two elements to form two different compounds. An example is carbon dioxide CO2 and carbon monoxide CO. This is because two elements can form different types of bond and end up with different compounds.

There is a limited number of elements but a large number of compounds because of the above reason.

3 0

3 years ago

Read 2 more answers

Which of the following is NOT a physical property?

ICE Princess25 [194]

Answer:

reactivity is NOT a physical property

5 0

3 years ago

All of the following reactions can be described as displacement reactions except:____________.

Lady_Fox [76]

Answer:

Explanation:

The reaction that is not a displacement reaction from all the options is $C_6H_6_{(l)} + Cl_{2(g)} --> C_6H_5Cl_{(l)} + HCl_{(g)}$

In a displacement reaction, a part of one of the reactants is replaced by another reactant. In single displacement reactions, one of the reactants completely displaces and replaces part of another reactant. In double displacement reaction, cations and anions in the reactants switch partners to form products.

Options a, c, d, and e involves the displacement of a part of one of the reactants by another reactant while option b does not.

Correct option = b.

8 0

3 years ago

A hypothetical covalent molecule, X–Y, has a dipole moment of 1.93 1.93 D and a bond length of 109 pm. 109 pm. Calculate the par

Gnesinka [82]

Answer:

q= 110.5 ke

Explanation:

Dipole moment is the product of the separation of the ends of a dipole and the magnitude of the charges.

μ = q * d

μ= Dipole moment (1.93 D)

q= partial charge on each pole

d= separation between the poles(109 pm).

e= electronic charge ( 1.60217662 × 10⁻¹⁹ coulombs)

So,

q= $\frac{1.93}{109 * 10^{-12} }$ coulombs

q = $\frac{1.93}{109 * 10^{-12} * 1.60217662 * 10^{-19} }$ e

q = 1.105 * 10⁵ e

q= 110.5 ke

4 0

3 years ago