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Sliva [168]
3 years ago
11

A hypothetical covalent molecule, X–Y, has a dipole moment of 1.93 1.93 D and a bond length of 109 pm. 109 pm. Calculate the par

tial charge on a pole of this molecule in terms of e , e, where e e is the charge on an electron.
Chemistry
1 answer:
Gnesinka [82]3 years ago
4 0

Answer:

q= 110.5 ke

Explanation:

Dipole moment is the product of the separation of the ends of a dipole and the magnitude of the charges.

μ = q * d

μ= Dipole moment (1.93 D)

q= partial charge on each pole

d= separation between the poles(109 pm).

e= electronic charge ( 1.60217662 × 10⁻¹⁹ coulombs)

So,

q= \frac{1.93}{109 * 10^{-12} } coulombs

q = \frac{1.93}{109 * 10^{-12} *  1.60217662 * 10^{-19} } e

q = 1.105 * 10⁵ e

q= 110.5 ke

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aleksley [76]

Answer:

When the animal has eaten food and the blood glucose level in the body increases. The pancreas cells in the body detects the increase in the blood glucose which leads to increase the insulin hormone.

This decreases the blood glucose level in the level. This is how the negative feedback works in the body if the level of glucose increases.

Negative feedback is the way by which the body maintains homeostasis and maintains equilibrium in the body.

6 0
3 years ago
Which statement is true about a reversible reaction?
vredina [299]

Answer:

The products react to reform the original reactants

E.g. Haber process of ammonia production

6 0
3 years ago
How many grams of methionine (MW = 149.21) are needed to make 20 mL of a 150 mM solution?
Leni [432]

Answer:

0.45 g

Explanation:

Step 1: Given data

  • Molar mass of methionine (M): 149.21 g/mol
  • Volume of the solution (V): 20 mL
  • Concentration of the solution (C): 150 mM

Step 2: Calculate the moles of methionine (n)

We will use the following expression.

n = C × V

n = 150 × 10⁻³ mol/L × 20 × 10⁻³ L

n = 3.0 × 10⁻³ mol

Step 3: Calculate the mass of methionine (m)

We will use the following expression.

m = n × M

m = 3.0 × 10⁻³ mol × 149.21 g/mol

m = 0.45 g

7 0
3 years ago
Look at the following balanced equation. How many atoms of oxygen (O) are present on the reactant side of the equation?
balu736 [363]

There are 6 atoms of oxygen on the reactant side of the following equation: 2Fe2O3 + 3C → 4Fe + 3CO2. Details about atoms can be found below.

<h3>How to find number of atoms?</h3>

The number of atoms of an element in a balanced equation is the amount of that element involved in the reaction.

According to this question, Iron oxide reacts with carbon to produce iron and carbon dioxide as follows:

2Fe2O3 + 3C → 4Fe + 3CO2

In this reaction, 2 × 3 atoms = 6 atoms of oxygen are present on the reactant side of the equation.

Learn more about number of atoms at: brainly.com/question/8834373

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4 0
2 years ago
Kenya has a pile of salt on the counter. She uses a pinch of it for a meal. Which of the following physical properties of the sa
AlladinOne [14]
The following choices are all extensive properties, meaning they do not change with the amount of the substance. Although, 3 of the properties, namely, density, solubility and thermal conductivity are temperature-dependent. Since the problem did not mention of heating, let's assume Kenya just used it directly for her meal. Among the choices, I think shape would change. Once you place it in the meal, you can no longer pinpoint the salt because it's shape has been changed.
7 0
3 years ago
Read 2 more answers
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