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atroni [7]
1 year ago
10

10. A spring whose composition is not completely known might be either bronze (sp gr 8.8) or brass (sp gr 8.4). It has a mass of

1.26 g when measured in air and 1.11 g in water. Which is it made of? ​
Physics
1 answer:
frez [133]1 year ago
7 0

The element used is of bronze.

Now before we find out how we got the answer as bronze, firstly let us understand about the device we are talking about. That is, spring.

What exactly is a spring?

A spring is defined as a device that changes its shape in response to an external force, returning to its original shape when the force is removed. If we apply force or pressure in this device, it will change its shape but the moment we stop applying force, it will come back to its original state.

This means that this device is made of something flexible. So, the material it is made up of should also be flexible in nature.

How to find out flexibility of spring?

Flexibility of spring can be found as q = f Q, where f is the spring flexibility.

Here, in this question, we are given the mass of element in air and water. This shows a slight comparison between the mass of that particular element in air and water and thus, we get to know it is trying to draw our attention towards density.

Here, we have mass in air and water, thus, we can determine the density.

From these numbers, we can know that the density given is of bronze.

Hence, the element used is Bronze.

To know more spring aggregate, refer : brainly.com/question/20215636

#SPJ4

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Assume that at sea-level the air pressure is 1.0 atm and the air density is 1.3 kg/m3.
scoundrel [369]

Answer

Pressure, P = 1 atm

air density, ρ = 1.3 kg/m³

a) height of the atmosphere when the density is constant

   Pressure at sea level = 1 atm = 101300 Pa

   we know

   P = ρ g h

   h = \dfrac{P}{\rho\ g}

   h = \dfrac{101300}{1.3\times 9.8}

          h = 7951.33 m

height of the atmosphere will be equal to 7951.33 m

b) when air density decreased linearly to zero.

  at x = 0  air density = 0

  at x= h   ρ_l = ρ_sl

 assuming density is zero at x - distance

 \rho_x = \dfrac{\rho_{sl}}{h}\times x

now, Pressure at depth x

dP = \rho_x g dx

dP = \dfrac{\rho_{sl}}{h}\times x g dx

integrating both side

P = g\dfrac{\rho_{sl}}{h}\times \int_0^h x dx

P =\dfrac{\rho_{sl}\times g h}{2}

 now,

h=\dfrac{2P}{\rho_{sl}\times g}

h=\dfrac{2\times 101300}{1.3\times 9.8}

  h = 15902.67 m

height of the atmosphere is equal to 15902.67 m.

6 0
3 years ago
An astronaut is traveling in a space vehicle moving at 0.490c relative to the Earth. The astronaut measures her pulse rate at 66
marta [7]

To solve the exercise it is necessary to use the reciprocal Lorenz factor of the special theory of relativity with the pulse rate.

\Xi = Pulse_{astronaut} * \alpha

Where,

\Xi = Pulse rate measured by earth observed

\alpha = Reciprocal Lorenz Factor

\alpha = \sqrt{1-\frac{v^2}{c^2}}

Here v is the velocity and c the light speed.

PART A) For the given values we can replace it at the previous equation,

\Xi = Pulse_{astronaut} *\sqrt{1-\frac{v^2}{c^2}}

\Xi = 66beats/min * \sqrt{1-\frac{(0.49c)^2}{c^2}}

\Xi = 57.5beats/min

PART B ) If the speed of vehicle is 0.94c:

\Xi = Pulse_{astronaut} *\sqrt{1-\frac{v^2}{c^2}}

\Xi = 66beats/min * \sqrt{1-\frac{(0.94c)^2}{c^2}}

\Xi = 22.5beats/min

8 0
3 years ago
the base of a rectangular vessel measure 10m by 18cm. water is poured into a depth of 4cm. (a) what is the pressure on the base?
Alex787 [66]

Answer:

a) P =392.4[Pa]; b) F = 706.32[N]

Explanation:

With the input data of the problem we can calculate the area of the tank base

L = length = 10[m]

W = width = 18[cm] = 0.18[m]

A = W * L = 0.18*10

A = 1.8[m^2]

a)

Pressure can be calculated by knowing the density of the water and the height of the water column within the tank which is equal to h:

P = density * g *h

where:

density = 1000[kg/m^3]

g = gravity = 9.81[m/s^2]

h = heigth = 4[cm] = 0.04[m]

P = 1000*9.81*0.04

P = 392.4[Pa]

The force can be easily calculated knowing the relationship between pressure and force:

P = F/A

F = P*A

F = 392.4*1.8

F = 706.32[N]

4 0
3 years ago
The Rite of Spring was composed by
7nadin3 [17]

The 'Rite of Spring' was composed by Igor Stravinsky.

7 0
4 years ago
Two objects are being lifted by a machine. One object has a mass of 2 kg, and is lifted at a speed of 2
kicyunya [14]

Answer:

Kinetic energy = (1/2) (mass) (speed²)

First object: (1/2) (2 kg) (2 m/s)² = 4 joules .

Second object: (1/2) (4 kg) (3 m/s)² = 18 joules .

The second object had more kinetic energy than the first one had.

Explanation:

8 0
3 years ago
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