Answer:
The answer is Temperature.
Answer:
The width of the strand of hair is 1.96 10⁻⁵ m
Explanation:
For this diffraction problem they tell us that it is equivalent to the diffraction of a single slit, which is explained by the equation
<h3> a sin θ =± m λ
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Where the different temrs are: “a” the width of the hair, λ the wavelength, θ the angle from the center, m the order of diffraction, which is the number of bright rings (constructive diffraction)
We can see that the diffraction angle is missing, but we can find it by trigonometry, where L is the distance of the strand of hair to the observation screen and "y" is the perpendicular distance to the first minimum of intensity
L = 1.25 m 100 cm/1m = 125 cm
y = 5.06 cm
Tan θ = y/L
Tan θ = 5.06/125
θ = tan⁻¹ ( 0.0405)
θ = 2.32º
With this data we can continue analyzing the problem, they indicate that they measure the distance to the first dark strip, thus m = 1
a = m λ / sin θ
a = 1 633 10⁻⁹ 1.25/sin 2.3
a = 1.96 10⁻⁵ m
a = 0.0196 mm
The width of the strand of hair is 1.96 10⁻⁵ m
Answer:
6.86 * 10^8 m
Explanation:
Parameters given:
Mass of hot gas, m = 2 kg
Gravitational Force, F = 618.2 N
Mass of Alpha Centauri, M = 2.178 * 10^30 kg
The gravitational force between two masses (the hot gas and Alpha Centauri) , m and M, at a distance, r, given as:
F = (G*M*m) / r²
Where G = gravitational constant
Therefore,
618.2 = (6.67 * 10^(-11) * 2.178 * 10^30 * 2) / r²
=> r² = (6.67 * 10^(-11) * 2.178 * 10^30 * 2) / 618.2
r² = 4.699 * 10^17 m²
=> r = 6.86 * 10^8 m
We are told that the hot gas is on the surface of Alpha Centauri, hence, the distance between both their centers is the radius of Alpha Centauri.
The mean radius of Alpha Centauri is 6.86 * 10^8 m.
(24 + 36) x 2 = 120
simple math. you're welcome.
"college student"
