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Dafna11 [192]
3 years ago
9

A charge of 4.4 10-6 C is located in a uniform electric field of intensity 3.9 105 N/C. How much work (in Joules) is required to

move this charge 50 cm along a path making an angle of 40
Physics
1 answer:
schepotkina [342]3 years ago
4 0

Answer:

The work required to move this charge is 0.657 J

Explanation:

Given;

magnitude of charge, q = 4.4 x 10⁻⁶ C

Electric field strength, E =  3.9 x 10⁵ N/C

distance moved by the charge, d = 50 cm = 0.5m

angle of the path, θ = 40°

Work done is given as;

W = Fd

W = FdCosθ

where;

F is the force on the charge;

According the coulomb's law;

F = Eq

F = 3.9 x 10⁵ x 4.4 x 10⁻⁶  = 1.716 N

W = FdCosθ

W = 1.716 x 0.5 x Cos40

W = 0.657 J

Therefore, the work required to move this charge is 0.657 J

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iris [78.8K]

Answer:

t = 1.659s

Explanation:

We can use the kinematics equations to solve this questions:

v = u + at

v^{2} = u^{2} +2as

where v = Final Velocity, u = initial velocity, a = acceleration, t = time, s = displacement

a) Given information from the question,

u = \frac{70km}{h} =\frac{(70*1000)m}{(1*3600)s} = 19.444m/s (Convert km/h to m/s first)

a = 2m/s^{2}

s = 35m

Now we can substitute these values into the 2nd kinematics equation to find v, final velocity.

v^{2} =(19.444)^{2} +2(2)(35)\\v=\sqrt{(19.444)^{2} +2(2)(35)} \\v= 22.761m/s (5.sf)\\

b) Now we have the final velocity, we can substitute the values into the first kinematics equation to find t , the time taken.

v = u + at

22.761 = 19.444 + 2t

2t = 22.761 - 19.444

t =\frac{22.761-19.444}{2}

t = 1.659s

7 0
2 years ago
it is required that an object weighing 8N be moved up ward at an acceleration of 2m/s what is the upward force needed ​
sesenic [268]

Answer:

F = 1.6 N

Explanation:

Newton's Second Law of Motion states that whenever an unbalanced force is applied on a body. It produces an acceleration in the body, in its own direction. The magnitude of the force is given by the following formula:

F = ma

where,

F = Force Required to Move the Object Upward = ?

m = mass of object

a = upward acceleration = 2 m/s²

but, we know that weight of object is given as:

Weight = mg

8 N = m(9.8 m/s²)

m = 0.8 kg

using values in the equation:

F = (0.8 kg)(2 m/s²)

<u>F = 1.6 N</u>

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Why doesn't the north star move?<br><br>i need the answer asap and i will give brainliest​
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☁️ Answer ☁️

annyeonghaseyo!

The answer is:

Because it takes the Earth a full year to move from one end of its orbit to the other, and because that distance is so tiny compared to the distance to the star, and because the star is aligned with the Earth's axis of rotation, it doesn't appear to ever move. The north pole coincidentally points at this star.

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