Answer:
Its pressure will be 0.54 atm at 100 K.
Explanation:
Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.
Gay-Lussac's law can be expressed mathematically as the quotient between pressure and temperature equal to a constant:
Studying two different states, an initial state 1 and a final state 2, it is satisfied:
In this case:
- P1= 1.75 atm
- T1= 50 °C= 323 K (being 0 C=273 K)
- P2= ?
- T2= 100 K
Replacing:
Solving:
P2= 0.54 atm
<u><em>Its pressure will be 0.54 atm at 100 K.</em></u>
This law<span> states that the pressure of a given amount of </span>gas<span> held at constant volume is directly proportional to the Kelvin temperature. Therefore, the variables are pressure and temperature. Hope this answers the question. Have a nice day.</span>
the force between the electron and the proton.
a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
the radial acceleration of the electron.
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
the speed of the electron.
c) Now use a = v² / r
where a was found above
and r was given
<span> the period of the circular motion.</span>
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given
Answer:
Free Energy (G) can either increase or decrease for a reaction when the temperature increases. It depends on the entropy (S) change. The change in a quantity is represented by the Greek letter delta. ... Hence, when the temperature increases the numeric value of the free energy becomes larger.
Explanation:
Answer: False
Explanation: just took on edge
