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Inessa05 [86]
2 years ago
15

Help with this plz!!!

Physics
1 answer:
Alex2 years ago
6 0

The answer is:

It is virtual and behind the mirror.

Mirrors produce images, either virtual or real.

Virtual images are produced when the image is behind the mirror. Real images are formed when they image is produced in front of the mirror.

So look at the image produced. It's small and found in behind the mirror.  This means that it is a virtual image. How do I know that its behind the mirror?

When you look at the diagram, the front side of the mirror is the blue side. This is a convex mirror.

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A fox with a thick fur would have a survival advantage over other foxes if
Nat2105 [25]
This question is poorly stated, but I assume you mean what conditions are needed. It would have to be cold outside, correct?
8 0
3 years ago
A ball is thrown straight up from ground level. It passes a 2-m-high window. The bottom of the window is 7.5 m off the ground. T
slamgirl [31]

Answer:

u=14.48m/s

Explanation:

From the question we are told that:

Height of window h=2m

Height of window off the ground h_g=7.5m

Time to fall and drop t=1.3s

 

Generally the Newton's equation motion  is mathematically given by

 s=ut+\frac{1}{2}at^2

Where

h=ut+\frac{1}{2}at^2

2=u1.3-\frac{1}{2}*9.8*1.3^2

2=u1.3-8.281

u=7.91m/s^2  

Generally the Newton's equation motion  is mathematically given by

2as=v^2-u^2

Where

-2gh_g=v^2-u^2

-2*9.8*7.5=(7.91)^2-u^2

-147=62.5681-u^2

u=\sqrt{209.5681}

u=14.48m/s

Therefore the  ball’s initial speed

u=14.48m/s

8 0
2 years ago
A 4 kg bowling bowl is sitting on a table 1 meter off the ground. How much potential energy does it have?
il63 [147K]

Answer:

\huge\boxed{\sf P.E. = 39.2\ Joules}

Explanation:

<u>Given Data:</u>

Mass = m = 4 kg

Acceleration due to gravity = g = 9.8 m/s²

Height = h = 1 m

<u>Required:</u>

Potential Energy = P.E. = ?

<u>Formula:</u>

P.E. = mgh

<u>Solution:</u>

P.E. = (4)(9.8)(1)

P.E. = 39.2 Joules

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
5 0
3 years ago
Question 9 please. How do you find instantaneous velocity and how do I sketch a velocity vs time graph from a position vs time o
pickupchik [31]

How do you find instantaneous velocity

Select a point on a distance-time curve graph. Draw a tangent to the curve at that point. Tangent -> hypotenuse of right angled triangle. Opp/adjacent in graph units is vel at that point -> in distance and/or time

3 0
3 years ago
A body of mass 1.0 kg initially at rest slides down an incline plane that is 1.0 m high and 10.0 m long. If the body experiences
Ksivusya [100]

Answer:

answer is

Explanation:

because

6 0
3 years ago
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