D. gravitational force. is your answer hope this helps
Do you have any answer choices?
Answer:
A 75.1 N and a direction of 152° to the vertical.
B 85.0 N at 0° to the vertical.
Explanation:
A) The interaction partner of this normal force has what magnitude and direction?
The interaction partner of this normal force is the component of the weight of the crate perpendicular to the ramp. <u>It has a magnitude of 85cos28° = 75.1 N and a direction of 180° - 28° = 152° to the vertical(since it is directed downwards perpendicular to the ramp).</u>
B) The normal and frictional forces are perpendicular components of the contact force exerted on the crate by the ramp. What is the magnitude and direction of the contact force?
Since this force has to balance the weight of the crate, its magnitude is 85.0 N. Its direction has to be vertically opposite to that of the weight.
Since the weight is 180° to the vertical (since it is directed downwards), this force is 0° to the vertical.
<u>So, this force has a magnitude of 85.0 N and a direction of 0° to the vertical.</u>
Answer:
Δp = 0.05 p
Explanation:
The moment is
p = m v
The uncertainty of the moment is
Δp = dp/dm Δm + dp/dv Δv
Like the uncertainty in the mass is zero
Δm = 0
ΔP = m Δv
We divide for the moment
Δp / p = Δv / v
They do not indicate that Δv / v = 0.05
Δp / p = 0.05
Δp = 0.05 p
In the case of a system consisting of two cars
p = m₁ v₁ + m₂ v₂
Δp = dp / dv₁ Δv₁ + dp / dv₂ Δv₂
Δp = m₁ Δv₁ + m₂ Δv₂
Δv₁ / v₁ = 0.05
Δv₁ = 0.05 v₁
Δv₂ / v₂ = 0.05
Δv₂ = 0.05 v₂
We replace
Δp = m₁ 0.05 v₁ + m₂ 0.05 v₂
Δp = 0.05 p
Answer:
Pure Food and Drug Act of 1906
Explanation:
The Pure Food and Drug Act of 1906 prohibited the sale of misbranded or adulterated food and drugs in interstate commerce and laid a foundation for the nation's first consumer protection agency, the Food and Drug Administration
