Answer:
11.87 ms⁻¹
Explanation:
You can use the kinematic equation
v² = u² + 2as
Where v = final velocity
u = initial velocity
a = acceleration
s = displacement
v² = 9² + 2×1.5×20
So you get v = 11.87 ms⁻¹
Tension force transmitted through the chains.
The answer is B hope this helps
That depends on how 'x' is related to 'y' and 'z' ... like the angles between all of them, and whether they're all on the same planet. A drawing would sure help.
Answer:
Explanation:
Incomplete question but for understanding.
We want to find the electrical force between two charges, then you can use the coulombs law which states that the force of attraction or repulsion between two charges is directly proportional to the product of the two charges and inversely proportional to the square of their distance apart,
So,
F = kq1•q2 / r²
Where k is a constant and it is given as
K = 8.99 × 10^9 Nm²/C²
q1 and q2 are the charges and in this question it is not given, so the question is incomplete. Let assume that,
q1 = - 1.609 × 10^-19 C electron
q2 = 1.609 × 10^-19 C proton
Since unlike charges attract, then it is force of attraction
Also, r is the distance apart and it is not given, let assume the distance between the two charges is 2 × 10^-5m
Then,
F = kq1•q2 / r²
F = 8.99 × 10^9 × 1.609 × 10^-19 × 1.609 × 10^-19 / (2 × 10^-5)²
F = 5.82 × 10^-19 N
