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Brrunno [24]
3 years ago
9

.What​ ​is​ ​the​ ​momentum​ ​of​ ​a​ ​car​ ​with​ ​a​ ​mass​ ​of​ ​1,300​ ​kg​ ​traveling​ ​north​ ​at​ ​a​ ​speed​ ​of 28​ ​m/

s?the​ ​momentum​ ​of​ ​the​ ​car​
Physics
1 answer:
Maksim231197 [3]3 years ago
3 0
44,563 m/s
hopoe this helps
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A carpenter builds an exterior house wall with a layer of wood 3.0 cm thick on the outside and a layer of Styrofoam insulation 2
Leno4ka [110]

Answer:

A. T=15.54 °C

B. Q/A= 0.119 W/m2

Explanation:

To solve this problem we need to use the Fourier's law for thermal conduction:

Q= kA\frac{dT}{dx}

Here, the rate of flow per square meter must be the same through the complete wall. Therefore, we can use it to find the temperature at the plane where the wood meets the Styrofoam as follows:

\frac{Q}{A} =\frac{T_1-T_0}{d_w}k_w=\frac{T_2-T_1}{d_s}k_s\\T_1(\frac{k_w}{d_w}+\frac{k_s}{d_s})=T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}\\T_1=\frac{T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}}{\frac{k_w}{d_w}+\frac{k_s}{d_s}}\\T_1= 15.54 \°C

Then, to find the rate of heat flow per square meter, we have:

\frac{Q}{A}=\frac{T_1-T_0}{d_w}k_w=0.119 \frac{W}{m^2}\\\frac{Q}{A}=\frac{T_2-T_1}{d_s}k_s= 0.119 \frac{W}{m^2}

T_0: Temperature \ in \ the \ house\\T_1: Temperature \ at \ the \ plane \ between \ wood \ and \ styrofoam\\T_2: Temperature \ outside\\k_w: k \ for \ wood\\d_w: wood \ thickness\\k_s: k \ for \ styrofoam\\d_s: styrofoam \ thickness

7 0
3 years ago
Which graph represents a nonlinear relationship? 40 40 40 40 30 30 30 30 20 از مسیر 20 20 20 10 10 10 10 0 0 0 0 2 4 6 0 2 4 6 0
Doss [256]

Explanation:

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7 0
2 years ago
Is the following chemical equation balanced?<br><br> MgI2 + Br2 MgBr2 + I2 <br><br> yes<br><br> no
Brums [2.3K]

Yes

Explanation:

This chemical equation:

Mg I_2 + Br_2 \rightarrow Mg Br_2 + I_2

is balanced, because the number of atoms of each element is the same on the reactant side and on the product side. In fact:

- Mg: one atom on the left, one on the right

- I: 2 atoms on the left, and 2 on the right

- Br: 2 atoms on the left, and 2 on the right

So, the reaction is balanced.

3 0
3 years ago
Read 2 more answers
James has a mass of 98 kg and Basma has a mass of 59 kg. James is running at 3.0 m/s, while Basma is running at 4.0 m/s.
belka [17]

a. The most momentum is attained by James.

b. The resultant force acting on her is 90.77N.

c. Time taken for him to stop is  3.24 s

<h3>What is momentum?</h3>

Momentum of any object is the product of the velocity of the object and its mass.

P =mv

James has a mass of 98 kg and Basma has a mass of 59 kg. James is running at 3.0 m/s, while Basma is running at 4.0 m/s.

a.

Substitute the values, we get

P jane= 98 kg x 3

P jane= 294 kg.m/s

Momentum of Basma, is

P Basma = 59 kg x 4

P Basma = 236  kg.m/s

Therefore, the momentum is large for James.

b. Basma approaches a road, so she stops quickly. It takes her 2.6 seconds to stop. The resultant force acting on her

F. t = P Basma

F =[ 236/2.6

F = 90.77 N

Thus, the resultant force on Basma is 90.77 N.

c. James also stops for the road. If he were to have the same resultant force acting on him, Time taken for him to stop is

F = 90.77 = P james/t

t = 294 / 90.77

t = 3.24 s

Thus, time taken for James to stop for the same resultant force is  3.24 s

Learn more about momentum.

brainly.com/question/4956182

#SPJ1

5 0
2 years ago
A chair of mass 12.0 kg is sitting on the horizontal floor; the floor is not frictionless. You push on the chair with a force F
Tanya [424]

Answer: Normal force, N = 141.64 Newton

Explanation:

All the forces acting on the system and described in free body diagram  are:

1) gravitational pull in downward direction  

2) Normal force in upward direction

3) External force of 40 N acting at an angle of 37° with the horizontal can be resolved in two rectangular components:

  i) F Cos 37° along the horizontal plane  in forward direction and

  ii) F Sin 37° along the vertical plane in downward direction

Applying the Newton's second law, net forces in the vertical plane are:

Net force, f = N - (mg + F Sin 37°)

As there is no acceleration in the vertical plane hence, net force f = 0.

So,

N - (mg + F Sin 37°) = 0

Adding (mg + F Sin 37°) both the sides in above equation, we get

N = mg + F Sin 37°

N = 12 \times 9.8 + 40 \times 0.601      because (Sin 37° = 0.601)

N = 117.6 + 24.04

N = 141.64 Newton

3 0
3 years ago
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