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Brrunno [24]
4 years ago
9

.What​ ​is​ ​the​ ​momentum​ ​of​ ​a​ ​car​ ​with​ ​a​ ​mass​ ​of​ ​1,300​ ​kg​ ​traveling​ ​north​ ​at​ ​a​ ​speed​ ​of 28​ ​m/

s?the​ ​momentum​ ​of​ ​the​ ​car​
Physics
1 answer:
Maksim231197 [3]4 years ago
3 0
44,563 m/s
hopoe this helps
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For the hypothetical reaction A → B, calculate the average rate of disappearance of A if the initial concentration of A is 0.91
marishachu [46]

Answer:

The right answer is 8.9 x 10^-3 M/min

Explanation:

           A → B

-d [A]/dt  = K [A]

ΔA/Δt     = - (C2 -C1)/t2 - t1

               = - (0.11 - 0.91)/90

               = 8.9 x 10^-3 M/min

7 0
3 years ago
Heart cells must contract simultaneously to move blood.
krek1111 [17]

Answer:

<u>A</u>

Explanation:

The heart cells must contract simultaneously to move blood.

This means that it needs to act fast and efficiently.

Therefore, the connections among heart cells are characterized by :

  • having many branches
  • having many communicating junctions

The correct option should be <u>A</u>

4 0
3 years ago
Read 2 more answers
A sealed tank containing seawater to a height of 10.5 mm also contains air above the water at a gauge pressure of 2.95 atmatm. W
weqwewe [10]

Answer:

The water is flowing at the rate of 28.04 m/s.

Explanation:

Given;

Height of sea water, z₁ = 10.5 m

gauge pressure, P_{gauge \ pressure} = 2.95 atm

Atmospheric pressure, P_{atm} = 101325 Pa

To determine the speed of the water, apply Bernoulli's equation;

P_1 + \rho gz_1 + \frac{1}{2}\rho v_1^2 = P_2 + \rho gz_2 + \frac{1}{2}\rho v_2^2

where;

P₁ = P_{gauge \ pressure} + P_{atm \ pressure}

P₂ = P_{atm}

v₁ = 0

z₂ = 0

Substitute in these values and the Bernoulli's equation will reduce to;

P_1 + \rho gz_1 + \frac{1}{2}\rho v_1^2 =  P_2 + \rho gz_2 + \frac{1}{2}\rho v_2^2\\\\P_1 + \rho gz_1 + \frac{1}{2}\rho (0)^2 =  P_2 + \rho g(0) + \frac{1}{2}\rho v_2^2\\\\P_1 + \rho gz_1 =  P_2 + \frac{1}{2}\rho v_2^2\\\\P_{gauge} + P_{atm} + \rho gz_1 = P_{atm} + \frac{1}{2}\rho v_2^2\\\\P_{gauge} +  \rho gz_1 =  \frac{1}{2}\rho v_2^2\\\\v_2^2 = \frac{2(P_{gauge} +  \rho gz_1)}{\rho} \\\\v_2 = \sqrt{ \frac{2(P_{gauge} +  \rho gz_1)}{\rho} }

where;

\rho is the density of seawater = 1030 kg/m³

v_2 = \sqrt{ \frac{2(2.95*101325 \ + \  1030*9.8*10.5 )}{1030} }\\\\v_2 = 28.04 \ m/s

Therefore, the water is flowing at the rate of 28.04 m/s.

7 0
3 years ago
What is the starting and final energy for a battery?
EleoNora [17]
Electrical energy is the starting and final energy of a battery
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3 years ago
Which statement about magnetic poles is accurate?
Mademuasel [1]
I see I'm late but I believe it's A. , opposites attract. I'm taking the test right now lol
6 0
4 years ago
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