1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
adelina 88 [10]
3 years ago
14

Show how you could prepare each of the following amines from benzaldehyde by reductive amination:

Chemistry
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

Check explanation.

Explanation:

Reductive amination is also known as reductive alkylation. Reductive amination is an good chemical reaction for the conversion of of carbonyl group into amine.

These are the steps to follow for the reaction;

(1). Step one: carbonyl group(either an aldehyde or a ketone) is used to convert amine to form an imine. The pH of the reaction should be slightly acidic.

(2). Step 2: the imine from step one is then converted into iminium ion under acidic condition too(for protonation).

(3). Step 3: the iminium ion is then reduced to the amine.

The equation of reaction are in the attached file.

Note: the attached picture is labelled (A) to (D).

Reaction A is the reaction of benzaldehyde with Benzylamine, B is the reaction of benzaldehyde with dibenzylamine, C is the reaction of benzaldehyde with N,N-Dimethylbenzylamine and D is the reaction of benzaldehyde with N-Benzylpiperidine.

You might be interested in
Identify two ways that the rate of a chemical reaction could be increased
Svetlanka [38]
Increase the Surface Area of the Reactants. Increasing the surface area of the reactants increases the rate of the reaction. More surface area means more collisions of the reactant molecules and an increased rate of the reaction. This occurs when reactants are made to react in powdered form
7 0
3 years ago
A student measures the mass of an 8 cm^3 block of brown sugar to be 12.9 g. What is the density of
Oduvanchick [21]

Answer:

1.6125 g/cm^3

Explanation:

Density= mass/volume

4 0
3 years ago
Find the mass of 4.5 moles of H3PO4
Contact [7]

Hey there!

H₃PO₄

Find molar mass.

H: 3 x 1.008 = 3.024

P: 1 x 30.97 = 30.97

O: 4 x 16 = 64

---------------------------------

                  97.994 grams

The mass of 1 mole of H₃PO₄ is 97.994 grams.

We have 4.5 moles.

97.994 x 4.5 = 440

The mass of 4.5 moles of H₃PO₄ is 440 grams.

Hope this helps!

6 0
3 years ago
Explain the relationship between an individual and a Society​
Rufina [12.5K]

Answer:

the relationship between an individual and a society is society doesn't exist independently without an individual .the individual lives and acts within society but society is nothing ,in spite of the combination of individual s for cooperation effort.

6 0
3 years ago
How much does one mole of NH3 weigh?
Leokris [45]
17.031 g/mol Hope this helps you
6 0
3 years ago
Other questions:
  • A glass of water contains 1.2 x 1024 molecules of water. An additional 4.0 moles of water are poured into the glass. How many mo
    15·1 answer
  • What functional group was mainly responsible for the damage of mucous membranes of the mouth and gut in patients that used salic
    11·1 answer
  • Water and methane have similar molar masses. methane changes from liquid to a gas. what could account for the difference
    6·1 answer
  • STP is:
    6·1 answer
  • In an experiment, onion plants of different ages were exposed to various amounts of caffeine to determine the effect of caffeine
    7·1 answer
  • Why do atomic models change over time
    14·1 answer
  • If 0.00872 mol neon gas at a particular temperature and pressure occupies a volume of 211 mL, what volume would 0.00701 mol neon
    14·1 answer
  • How many moles are equal to 3.5 grams of beryllium
    11·1 answer
  • How to change τhe color of silver mercury to red???
    12·1 answer
  • Give an example of a non-biological chemical reaction that involves carbon. Name the process that converts a solid compound into
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!