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adelina 88 [10]
2 years ago
14

Show how you could prepare each of the following amines from benzaldehyde by reductive amination:

Chemistry
1 answer:
dimulka [17.4K]2 years ago
7 0

Answer:

Check explanation.

Explanation:

Reductive amination is also known as reductive alkylation. Reductive amination is an good chemical reaction for the conversion of of carbonyl group into amine.

These are the steps to follow for the reaction;

(1). Step one: carbonyl group(either an aldehyde or a ketone) is used to convert amine to form an imine. The pH of the reaction should be slightly acidic.

(2). Step 2: the imine from step one is then converted into iminium ion under acidic condition too(for protonation).

(3). Step 3: the iminium ion is then reduced to the amine.

The equation of reaction are in the attached file.

Note: the attached picture is labelled (A) to (D).

Reaction A is the reaction of benzaldehyde with Benzylamine, B is the reaction of benzaldehyde with dibenzylamine, C is the reaction of benzaldehyde with N,N-Dimethylbenzylamine and D is the reaction of benzaldehyde with N-Benzylpiperidine.

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A gas is at a pressure of 3.70 atm. What is this pressure in kilopascals?
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Answer:
                =   374.90 kPa 

Calculation:
                  As we know atm and kiloPascal are related to each other as,

                                         1 atm  =  101.325 kPa
So,
                                    3.70 atm  =   X
Solving for X,
                                     X  = (3.70 atm × 101.325 kPa) ÷ 1 atm

                                     X  =  374.90 kPa 
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How many grams of ammonia (NH3) can be produced by the synthesis of excess hydrogen gas (H2) and 253.8 grams of nitrogen gas (N2
kogti [31]

Answer:

308.2 g of NH₃.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3H₂ + N₂ —> 2NH₃

Next, we shall determine the mass of N₂ that reacted and the mass of NH₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of N₂ = 2 × 14 = 28 g/mol

Mass of N₂ from the balanced equation = 1 × 28 = 28 g

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Mass of NH₃ from the balanced equation = 2 × 17 = 34 g

Summary:

From the balanced equation above,

28 g of N₂ reacted to produce 34 g of NH₃.

Finally, we shall determine the mass of NH₃ produced by the reaction of 253.8 g of N₂. This can be obtained as illustrated below:

From the balanced equation above,

28 g of N₂ reacted to produce 34 g of NH₃.

Therefore, 253.8 g of N₂ will react to produce = (253.8 × 34)/28 = 308.2 g of NH₃.

Thus, 308.2 g of NH₃ were obtained from the reaction.

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