the resistance of the cable is 582.9 ohms
we are given the length of the cable which is 3 km, of 1.5 mm in, the diameter and resistivity of copper which is 1.72 m
The formula we are referring to for calculating the resistance of the cable is
R = ρl/A.
As there are 19 strands of copper conductors, so the resistance will be
R = 19( ρl/A)
Here ρ is the resisitivity = 1.72 , l is the length = 3(1+0.05)*10³3= 3150 m
A=pie/4(1.5 x 10⁻³)^2 =1.766 x 10⁻⁶ =1.766 x 10^-6
Substituting the values in the formula we get
R = 19 ( 1.72*3150 )/1.766 x 10⁻⁶
= 582.9 ohm
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<span>Radio waves just like light waves can be reflected refracted and diffracted and polarized. The answer is True. </span>These characteristics are the common phenomena for electromagnetic (EM) waves, and Radio Waves are electromagnetic Waves so much so that they obey reflection, refraction, and diffraction.
Answer:
Atoms are single neutral particles.
example: Ne, O
Molecules are neutral particles made of two or more atoms bonded together.
example:O2,HCl
Answer: Take your pick
Explanation:
if they are all in parallel 1 /(1/100 + 1/300 + 1/50) = 30 Ω
if 50 is in parallel with 2 in series 1 / (1/(100 + 300) + 1/50) = 44.444...Ω
if 100 is in parallel with 2 in series 1 / (1/(50 + 300) + 1/100) = 77.777...Ω
if 300 is in parallel with 2 in series 1 / (1/(100 + 50) + 1/300) = 100 Ω
If 50 is in series with 2 in parallel 50 + 1/(1/100 + 1/300) = 125 Ω
If 100 is in series with 2 in parallel 100 + 1/(1/50 + 1/300) = 142.857...Ω
If 300 is in series with 2 in parallel 300 + 1/(1/50 + 1/100) = 333.333...Ω
If they are all in series 100 + 300 + 50 = 450 Ω
