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Ostrovityanka [42]
3 years ago
6

Hola puntos gratis !!!!!!!!!!!!!!!!!

Physics
2 answers:
mina [271]3 years ago
7 0

Answer:

gracias

Explanation:

Sloan [31]3 years ago
4 0

Hello.

Brainly points can be used for better situations, brainly points are experience that you receive by answering well.

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Suppose a skydiver (mass = 80kg) is falling toward the Earth. Calculate the skydiver’s gravitational potential energy at a point
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Ep is gravitational potential energy
m is mass (kg)
g is gravitational field strength (N/kg)
h is height (m)

Ep= mgh
= 80kg*9.8N/kg*100m
= 78 400 J
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What are the rarefaction and compression regions of a guitar string
andrezito [222]

Answer:

The middle and end of the string respectively

Explanation:

Rarefaction means region of maximum displacement and compression means region of minimum displacement, hence.

We expect a maximum displacement at the middle of the string because it is said to vibrate greatest at this point and conversely vibrate least at the end point which is the region of compression.

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Compared to its weight on Earth, a 10-kg object on the moon will weigh Question 9 options: less. the same amount. more.
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it will weigh less on the moon.

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Radio waves travel 300,000,000 m/s. The frequency is 101,700,000. ehats the wavelength​
Nesterboy [21]

Answer:

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frequency(f)= speed of sound(c)/wavelength(λ)

for wavelength we swipe it with frequency as follows

λ=c/f

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8 0
3 years ago
A plane has a mass of 360,000 kg takes-off at a speed of 300 km/hr. i) What should be the minimum acceleration to take off if th
melomori [17]

Answer:

i) the minimum acceleration to take off is 22500 km/h²

ii) the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) required force that the engine must exert to attain acceleration is 625 kN

Explanation:

Given the data in the question;

mass of plane m = 360,000 kg

take of speed v = 300 km/hr = 83.33 m/s

i)

What should be the minimum acceleration to take off if the length of the runway is 2.00 km

from Newton's equation of motion;

v² = u² + 2as

we know that a plane starts from rest, so; u = 0

given that distance S = 2 km

we substitute

(300)² = 0² + ( 2 × a × 2 )

90000 = 4 × a

a = 90000 / 4

a = 22500 km/h²

Therefore,  the minimum acceleration to take off is 22500 km/h²

ii) At this acceleration, how much time would the plane need from starting to takeoff.

from Newton's equation of motion;

v = u + at

we substitute

300 = 0 + 22500 × t

t = 300 / 22500

t = 0.0133 hrs

Therefore, the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) What force must the engines exert to attain this acceleration

we know that;

F = ma

acceleration a = 22500 km/hr² = 1.736 m/s²

so we substitute

F = 360,000 kg × 1.736 m/s²

F =  624960 N

F = 625 kN

Therefore, required force that the engine must exert to attain acceleration is 625 kN

5 0
3 years ago
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