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lisabon 2012 [21]
3 years ago
6

PLEASE ANSWER QUICK!! What happens at the condensation point?A. Molecules of a liquid heat up and begin to convert to a gaseous

state.
B. Molecules of a solid speed up and begin to turn to a liquid state.
C. Molecules of a liquid slow down and start to convert to a solid state.
D. Molecules of a gas slow down and change to a liquid state.
Physics
1 answer:
Nastasia [14]3 years ago
4 0

Answer:

D. Molecules of a gas slow down and change to a liquid state.

Explanation:

  • Condensation refers to a process by which a gas changes from gaseous state to liquid state. For example, water vapor changes to from the state of being a gas to liquid state water.
  • Condensation is the opposite of evaporation and occurs when gaseous particles slow down and change into liquid state.
  • Heat energy is lost during condensation and gaseous molecules lose kinetic energy making them to slow down and thus changing to liquid state,
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Answer:

a = 0.8 m/s^2

Explanation:

Force equation: F = ma

F = ma -> a = F/m = 2.8*10^3 N / 3.5*10^3 kg = 0.8 m/s^2

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The bones of the forearm (radius and ulna) are hinged to the humerus at the elbow. The biceps muscle connects to the bones of th
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Answer:

F_b  = 1647.92 N

Explanation:

Given:

length of the arm, r = 0.465 m

distance of forearm from elbow, r' = 2.15 cm = 0.0215 m

Mass of the forearm, M = 2.45 kg

Mass of the object, m = 6.55 kg

Let, the Force by bicep be, F_b

under the motionless condition, the net moment about elbow is zero

thus,

F_b × 0.0215 - Mg × (0.465/2) - mg × (0.465) = 0

or

F_b × 0.0215 - 2.45 × 9.8 × (0.465/2) - 6.55 × 9.8 × (0.465) = 0

or

F_b × 0.0215 - 5.582 - 29.848 = 0

or

F_b  = 1647.92 N

hence, the force exerted by the elbow is 1647.92 N

4 0
3 years ago
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What engine thrust is required for a rocket of mass 35 kg to leave the launching pad? 3.5 N. 35 N. 351 N. 3,500 N. 35,000 N.
soldi70 [24.7K]

In order for the object to move upward, it needs an upward force
that's at least equal to its own weight.

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3 years ago
A speaker at the front of a room and an identical speaker at the rear of the room are being driven at 456 Hz by the same sound s
vampirchik [111]

Answer:

2.97795 Hz

Explanation:

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v_r = Relative speed between the speakers and the student = 1.12 m/s

f' = Actual frequency of sound = 456 Hz

Frequency of sound heard as the student moves away from one speaker

f_1=f'\dfrac{v-v_r}{v}\\\Rightarrow f_1=456\dfrac{343-1.12}{343}\\\Rightarrow f_1=454.51102\ Hz

Frequency of sound heard as the student moves closer to the other speaker

f_2=f'\dfrac{v+v_r}{v}\\\Rightarrow f_2=456\dfrac{343+1.12}{343}\\\Rightarrow f_2=457.48897\ Hz

The difference in the frequencies is

f_2-f_1=457.48897-454.51102=2.97795\ Hz

The student hears 2.97795 Hz

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3 years ago
What are the disadvantages of wind power?
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