Answer:
= 33.33 cm
Explanation:
Given:
When mass,
=21 kg
distance travelled is
= 140 cm
When mass,
=5 kg
distance travelled is
= ?
Hooke's law state that within elastic limit, when an external force is applied to a body, the body gets deformed and when the force is released the gets back to its original form.
Therefore according to the question,


= 33.33 cm
Distance travelled is 33.33 cm when mass is 5 kg.
Answer:
h f = W + KE
Input energy equals work function plus KE of emitted electron
W = 6.63E-34 * 2.5E15 - 6.3 * 1.6E-19
W = 6.63 * 2.5 * 10^-19 - 10.1 * E-19 ev (1ev = 1.6E-19 J)
W = (16.6 - 10.1)E-19 = 6.5E-19 J
h f = 6.5E-19 J for electrons to be emitted with zero KE
f = 6.5E-19 / 6.63E-34 = .98E-15 / sec = 9.8E-14 / sec (threshold)
Answer:b
Explanation:
im in fifth grade so i guessd. gl tho heh.