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Nana76 [90]
3 years ago
13

A police car is moving to the left at 34m/sec while its siren is emitting a 600Hz tone. What tone would you hear if you were par

ked along side the road
Physics
1 answer:
faust18 [17]3 years ago
8 0

Answer:

545.89\ \text{Hz}

Explanation:

v_o = Velocity of observer = 0

v_s = Velocity of source = 34 m/s

v = Speed of sound in air = 343 m/s

f = Emitted frequency = 600 Hz

Doppler effect will be observed

f_o=f(\dfrac{v+v_o}{v+v_s})\\\Rightarrow f_o=600(\dfrac{343+0}{343+34})\\\Rightarrow f_o=545.89\ \text{Hz}

The frequency heard will be 545.89\ \text{Hz}.

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Doug is doing work. Without knowing exactly what he is doing, which can be said about the work he is doing?
WARRIOR [948]
<h3>Answer;</h3>

<em>Energy is transferred.</em>

<h3>Explanation;</h3>
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  • Work is measured in Joules.
  • Energy on the other hand, is the ability to do work.
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4 years ago
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What is the difference between heat exhaustion and heat stroke?
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I believe the answer is D, Heat exhaustion involves a lack of sweating, while heat stroke involves extreme sweating. Also just to add the on if heat exhaustion is left untreated then it could turn into a heat stroke.
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3 years ago
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An oil droplet is sprayed into a uniform electric field of adjustable magnitude. The 0.11 g droplet hovers
ohaa [14]

Answer:

The direction of the field is downward, and negatively charged particles will experience an upwards force due to the field.

F = N e E     where E is the value of the field and N e the charge Q

M g = N e E      and M g is the weight of the drop

N = M g / (e E)

N = 1.1E-4 * 9.8 / (1.6E-19 * 370) = 1.1 * 9.8 / (1.6 * 370) * E15 = 1.82E13

.00011 kg is a very large drop

Q = N e = M g / E = .00011 * 9.8 / 370 = 2.91E-6 Coulombs

Check:     N = Q / e = 2.91E-6 / 1.6E-19 = 1.82E13   electrons

7 0
3 years ago
When jumping down from a table to the ground, it is helpful to bend your knees when you hit the ground because...
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Answer:

This reduces the average force applied during the landing process/ or you can say it reduces the impact your body takes.

Explanation:

7 0
3 years ago
An attack helicopter is equipped with a 20- mm cannon that fires 87 g shells in the forward direction with a muzzle speed of 853
uysha [10]

Answer

given,

mass of the shell = 87 g = 0.087 Kg

speed of the muzzle = 853 m/s

mass of the helicopter = 4410 kg

A burst of 176 shell fired in 2.93 s

resulting average force = ?

momentum of the shell = m v

                                       = 0.087 x 853

                                       = 74.21 kgm/s

momentum of 176 shell is = 176 p

                                          = 176 x 74.21

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momentum of helicopter = - 13060.96 kgm/s

amount of speed reduce a = \dfrac{13060.96}{M}

                                          a= \dfrac{13060.96}{4410}

                                          a = 2.96 m/s²

velocity  = \dfrac{2.96}{2.93}

      v = 1.01 m/s

5 0
3 years ago
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