Answer:
There are 2.258 x 10^24 molecules of CO2 in 165 grams of CO2.
Explanation:
First you have to calculate the molar mass of carbon dioxide ⇒ 44 grs/mol. Then,
44 grs ------------- 1 mol CO2
165 grs ------------ x = 3.75 moles of CO2.
Then, from Avogadros constant we have that there are 6.022 x 10^23 molecules in 1 mol. So,
1 mol CO2 ---------------- 6.022 x 10^23 molecules CO2
3.75 moles CO2-------- x = 2.258 x 10^24 molecules CO2.
There are 2.258 x 10^24 molecules CO2 in 165 grams of CO2.
Answer:
HF is the acid
Explanation:
The Brønsted-Lowry theory defines the acids and bases in chemistry as follows:
An acid is the species that can donate a proton
A base can accept protons.
In the reaction:
HF(aq) + NH₃(aq) → NH₄⁺(aq) + F⁻(aq)
As you can see, HF can donate its proton to produce F⁻: HF is the acid
<em>In the same way, NH₃ is accepting a proton, NH₃ is the base.</em>
Mass of Pd = 95.78 g which is close the the variant E) 95.89
Explanation:
To calculate the number of moles of palladium (Pd) we use the following formula:
number of moles = mass / atomic weight
mass = number of moles × atomic weight
mass of Pd = 0.90 × 106.42
mass of Pd = 95.78 g
Learn more about problems with number of moles:
brainly.com/question/3262
Answer:
396 g OF CO2 WILL BE PRODUCED BY 270 g OF GLUCOSE IN A RESPIRATION PROCESS.
Explanation:
To calculate the gram of CO2 produced by burning 270 g of gucose, we first write out the equation for the reaction and equate the two variables involved in the question;
C6H12O6 + 6O2 -------> 6CO2 + 6H2O
1 mole of C6H12O6 reacts to form 6 moles of CO2
Then, calculate the molar mass of the two variables;
Molar mass of glucose = ( 12 *6 + 1* 12 + 16* 6) g/mol = 180 g/mol
Molar mass of CO2 = (12 + 16 *2) g/mol = 44 g/mol
Next is to calculate the mass of glucose and CO2 involved in the reaction by multiplying the molar mass by the number of moles
1* 180 g of glucose yields 6 * 44 g of CO2
180 g of glucose = 264 g of CO2
If 270 g of glucose were to be used, how many grams of CO2 will be produced;
so therefore,
180 g of glucose = 264 g of CO2
270 g of glucose = x grams of CO2
x = 264 * 270 / 180
x = 71 280 / 180
x = 396 g of CO2.
In other words, 396 g of CO2 will be produced by respiration from 270 g of glucose.
