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3 years ago

Phentyfloroform contains 57.54% C, 3.45% H, and 39.01% F. What is its empirical formula?

Chemistry

1 answer:

kap26 [50]3 years ago

6 0

Answer:

Empirical formula is C₇H₅F₃

Explanation:

Given data:

Percentage of hydrogen = 3.45%

Percentage of carbon = 57.54%

Percentage of fluorine = 39.01%

Empirical formula = ?

Solution:

Number of gram atoms of H = 3.45 / 1.01 = 3.42

Number of gram atoms of F = 39.01 / 18.99 = 2.05

Number of gram atoms of C = 57.54/ 12.01 = 4.79

Atomic ratio:

C : H : F

4.79/2.05 : 3.42/2.05 : 2.05/2.05

2.34 : 1.67 : 1

C : H : F = 3(2.34 : 1.67 : 1 )

Empirical formula is C₇H₅F₃.

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Phentyfloroform contains 57.54% C, 3.45% H, and 39.01% F. What is its empirical formula?​

Phentyfloroform contains 57.54% C, 3.45% H, and 39.01% F. What is its empirical formula?