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zmey [24]
3 years ago
6

Phentyfloroform contains 57.54% C, 3.45% H, and 39.01% F. What is its empirical formula?​

Chemistry
1 answer:
kap26 [50]3 years ago
6 0

Answer:

Empirical formula is C₇H₅F₃

Explanation:

Given data:

Percentage of hydrogen = 3.45%

Percentage of carbon = 57.54%

Percentage of fluorine = 39.01%

Empirical formula = ?

Solution:

Number of gram atoms of H = 3.45 / 1.01 = 3.42

Number of gram atoms of F = 39.01 / 18.99 = 2.05

Number of gram atoms of C = 57.54/ 12.01 = 4.79

Atomic ratio:

            C                      :        H                :         F

           4.79/2.05         :     3.42/2.05      :       2.05/2.05

            2.34                 :        1.67                  :        1

C : H : F = 3(2.34 : 1.67 : 1 )

Empirical formula is C₇H₅F₃.

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Hope this helps and if it does, don't be afraid to rate my answer as well as maybe give it a "Thanks"? (Or even better a "Brainliest"). And if it’s not correct, I am sorry for wasting your time, and good luck finding the correct answer :)


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