KE=1/2mv^2
KE=1/2 x 5kg x (10m/s)^2
KE= 2.5kg x 100m^2/s^2
KE= 250 J
Answer:
0.345m
Explanation:
Let x (m) be the length that the spring is compress. If we take the point where the spring is compressed as a reference point, then the distance from that point to point where the ball is held is x + 1.1 m.
And so the potential energy of the object at the held point is:
where m = 1.3 kg is the object mass, g = 10m/s2 is the gravitational acceleration and h = x + 1.1 m is the height of the object with respect to the reference point
According to the conservation law of energy, this potential energy is converted to spring elastic energy once it's compressed
where k = 315 is the spring constant and x is the compressed length
x = 0.345 m or x = -0.263 m
Since x can only be positive we will pick the 0.345m
Answer:
The neutron core is completely destroyed
Explanation:
A earth - supernova is an explosion resulting to the death of a star that occurs close enough to the earth but this does not completely destroy a star. Supernovae are the most violent explosions in the universe. But they do not explode like a bomb explodes, blowing away every bit of the original bomb. Rather, when a star explodes into a supernova, its core survives. The reason for this is that the explosion is caused by a gravitational rebound effect and not by a chemical reaction. Stars are so large that the gravitational forces holding them together are strong enough to keep the nuclear reactions from blowing them apart. It is the gravitational rebound that blows apart a star in a supernova.
. Given- vf-112m/s, d-398m, Vi-0m/s (112 m/s)2 =
(0 m/s)2 + 2*(a)*(398 m)12544 m2/s2 = 0 m2/s2 + (796 m)*a12544 m2/s2 =
(796 m)*a(12544 m2/s2)/(796 m) = aa = 15.8 m/s26.