Answer:
v = 7.18_m/s
Explanation:
Velocity of the earth towards the ball is = velocity of the ball moving towards earth
For object in free fall, we have
Where
v = final velocity
u = initial velocity
g = acceleration due to gravity
t = time
S = height of ball above ground
v^2 = u^2 - 2×g×(-S)
= 0 + 2×9.8×2.63 = 51.55_m^2/s^2
Velocity of the ball just before it hits the ground is
v = 7.18_m/s
Answer:
D remove 1.5 ML of liquid.
Explanation:
Answer:
F = -49.1 10³ N
Explanation:
Let's use the kinematics to find the acceleration the acceleration of the bullet that they tell us is constant
² = v₀² + 2 a x
Since the bullet is at rest, the final speed is zero
x = 11.00 cm (1 m / 100 cm) = 0.110 m
0 = v₀² + 2 a x
a = -v₀² / 2 x
a = -1320²/(2 0.110)
a = -7.92 10⁶ m / s²
With Newton's second law we find the force
F = m a
F = 6.20 10⁻³ (-7.92 10⁶)
F = -49.1 10³ N
The sign means that it is the force that the tree exerts to stop the bullet