The direction of the magnetic force on the wire is west.
The magnetic force acting on the moving protons acts northward in the horizontal plane. If the thumb is up (current flows vertically up), the wrapped finger will be counterclockwise.
Therefore, the direction of the magnetic field is counterclockwise. Here, the magnetic field is pointing upwards (vertical magnetic field) and the electrons are moving east. Applying Fleming's left-hand rule here, we can see that the direction of force is along the south direction.
As the change in magnetic flux increases upwards, Lenz's law indicates that the induced magnetic field of the induced current must resist and the inside of the loop must be directed downwards. Using the right-hand rule, we can see that a clockwise current is induced.
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Answer:
8
Explanation:
Applying,
v = λf................ Equation 1
Where v = velocity/ speed of the wave, λ = wave length of the wave, f = number of waves the person surf in one seconds.
make f the subject of the equation
f = v/λ............ Equation 2
From the question,
Given: v = 1.6 m/s, λ = 24 m
Substitute these values into equation 2
f = 1.6/24
f = 0.0667 wave/seconds.
If,
in one seconds, the person surf a total wave crest of 0.0667
Therefore,
in one hours, he will surf a total wave crest of (0.0667×60×60) = 240 waves crest
He rides for every 30th wave crest,
Hence,
number of wave crest the person surf in one hour = 240/30 = 8
Answer: a) 10.4km
b) 0.62h
C) 17km/h
d) 9.1km/h
Explanation:
A) suppose you move in the positive direction of an x axis, from a first position of x1 = 0 to a second position of x2 at the station. That second position must be at x2 = 8.4 km + 2.0 km = 10.4 km.
B) time interval Dtwlk (= 0.50 h), but we don't know the driving time interval Dt/dr. However, we know that for the drive the displacement Dx/dr is 8.4 km and the average velocity vavg,dr is 70 km/h.
This average velocity is the ratio of the displacement for the drive to the time interval for the drive:
dv = dx/ dt
dt = dx/dv = 8.4/70 = 0.12h
t = ti + two
t = 0.12 + 0.50 = 0.62h
C) avg speed for the entire trip is the ratio of the displacement of 10.4 km for the entire trip to the time interval of 0.62 h for the entire trip.
Avg v = distance/time
10.4/0.62 = 16.8km/h
D) average speed is the ratio of the total distance you move to the total time interval you take to make that move. The total distance is 8.4 km + 2.0 km + 2.0 km = 12.4 km. The total time interval is 0.12 h + 0.50 h + 0.75 h = 1.37 h.
Avg speed = 12.4/1.37 = 9.1km/h
Initial speed = 0
final speed = v
acceleration = 5.1
time taken = 0.25
v=u+at
v=1.28 m /s
