All categories

3 years ago

Someone please help me, I’m so lost my brain hurts

Physics

2 answers:

tiny-mole [99]3 years ago

7 0

-- It takes 100 calories of heat to make 10 grams of the stuff 20° warmer.

How much of the heat warms each gram ?

-- It takes 10 calories of heat to make each gram of the stuff 20° warmer.

How much of the heat warms that gram each degree ?

-- It takes 1/2 calorie of heat to make each gram of the stuff 1° warmer.

The specific heat of that stuff is

(1/2 calorie) per gram per °C.

That's choice-3 .

maw [93]3 years ago

5 0

Explanation:

The answer is No. 3

0.5 cal/g°C

You might be interested in

A car traveling with constant speed travels 150 km in 7200s what is the speed of the car

Oksana_A [137]

Velocity is distance/time

so 150/7200=.0208km/s

unless you have to convert it to miles or something else. but use the formula!

5 0

3 years ago

I need help pls now plleeeeeeeeaaassseeeee

GrogVix [38]

Answer:

$r = \frac{v}{i} = v = ri \\ i = \frac{v}{r}$

4 0

3 years ago

Which equation is correct according to Ohm’s law? Which equation is correct according to Ohm’s law? A.) V = IR B.) I = R/V C.) R

vodomira [7]

Answer:

$V = IR$

Explanation:

Required

Which equation represents ohm's law?

Literally, ohm's law implies that current (I) is directly proportional to voltage (V) and inversely proportional to resistance (R).

Mathematically, this can be represented as:

$I\ \alpha\ \frac{V}{R}$

Convert the expression to an equation

$I\ =\ \frac{V}{R}$

Multiply both sides by R to make V the subject

$I\ * R\ =\ \frac{V}{R} * R$

$I\ * R\ =V$

Reorder

$V = I\ * R$

$V = IR$

<em>Option (a) is correct; Others are not</em>

6 0

3 years ago

Read 2 more answers

A 0.03 kg golf ball is hit off the tee at a speed of 34 m/s. The golf club was in contact with the ball for 0.003 s. What is the

Liula [17]

Answer:

The average force on ball by the golf club is 340 N.

Explanation:

Given that,

Mass of the golf ball, m = 0.03 kg

Initial speed of the ball, u = 0

Final speed of the ball, v = 34 m/s

Time of contact, $\Delta t=0.003\ s$

We need to find the average force on ball by the golf club. We know that the rate of change of momentum is equal to the net external force applied such that :

$F=\dfrac{\Delta p}{\Delta t}\\\\F=\dfrac{mv-mu}{\Delta t}\\\\F=\dfrac{mv}{\Delta t}\\\\F=\dfrac{0.03\ kg\times 34\ m/s}{0.003\ s}\\\\F=340\ N$

So, the average force on ball by the golf club is 340 N.

4 0

4 years ago

If an engine does 660 J of work in 10 seconds, its average power is ...

givi [52]

Answer:

66w

Explanation:

p=w/t

p=660/10

p=66

prolly a bad explanation but hope it helps...

4 0

3 years ago