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ollegr [7]
3 years ago
15

Someone please help me, I’m so lost my brain hurts

Physics
2 answers:
tiny-mole [99]3 years ago
7 0

-- It takes 100 calories of heat to make 10 grams of the stuff 20° warmer.

How much of the heat warms each gram ?

-- It takes 10 calories of heat to make each gram of the stuff 20° warmer.

How much of the heat warms that gram each degree ?

-- It takes 1/2 calorie of heat to make each gram of the stuff 1° warmer.

The specific heat of that stuff is

(1/2 calorie) per gram per °C.

That's choice-3 .

maw [93]3 years ago
5 0

Explanation:

The answer is No. 3

0.5 cal/g°C

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A 15-watt bulb is connected to a circuit that has a total of 60. Ω of resistance. How many electrons are passing through that bu
Mariulka [41]

Answer:

3.2075*10^16

Explanation:

Q=P/V just search up a converter and youll get 30V and so you do 15/30 which is a half and a single coulomb is 6.415*10^16 so you half it. I belive this is correct if you dont belive me wait for someone else smarter to answer and compare.

3 0
3 years ago
I need help with 5 please and thank you
Likurg_2 [28]

Answer: A

Explanation:

7 0
3 years ago
Which object has more gravitational potential energy? Use PE = m × g × h, where g = 9.8 meters/second2.
Andrew [12]
Gravitational potential energy can be calculated using the formula <span>PE = m × g × h, where g is the gravitational acceleration and is constant hence the energy is dependent directly to mass and the height of the object. Hence more PE is registered when the object is heavier and/or at greater initial height. </span>
6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP WILL GIVE BRAINLIEST ​
stealth61 [152]

Explanation

(m) is measured in kilograms (kg)

<h2>(F) is measured in newtons (N)</h2>

<h3>acceleration (a) is measured in metres per second squared (m/s²)</h3>
4 0
3 years ago
Read 2 more answers
An object is pushed from rest across a sheet of ice, accelerating at 8.0 m/s^2 [E] over a displacement of 1.05 m [E]. The object
tatiyna

Answer:

D_T=18.567m

Explanation:

From the question we are told that:

Acceleration a=8.0 m/s^2

Displacement d=1.05 m

Initial time t_1=6.0s

Final Time t_2=2.5s

Generally the equation for Velocity of 1.05 travel is mathematically given by

Using Newton's Law of Motion

 V^2=2as

 V=\sqrt{2*6*1.05}

 V=4.1m/s

Generally the equation for Distance traveled before stop is mathematically given by

 d_2=v*t_1

 d_2=3.098*4

 d_2=12.392

Generally the equation for Distance to stop is mathematically given by

Since For this Final section

Final velocity v_3=0 m/s

Initial velocity u_3=4.1 m/s

Therefore

Using Newton's Law of Motion

 -a_3=(4.1)/(2.5)

 -a_3=1.64m/s^2

Giving

 v_3^2=u^2-2ad_3

Therefore

 d_3=\frac{u_3^2}{2ad_3}

 d_3=\frac{4.1^2}{2*1.64}

 d_3=5.125m

Generally the Total Distance Traveled is mathematically given by

 D_T=d_1+d_2+d_3

 D_T=5.125m+12.392+1.05 m

 D_T=18.567m

6 0
3 years ago
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