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kvasek [131]
3 years ago
8

If an impulse of 400 Ns acts on an object for 15s, what is the force of the object?

Physics
1 answer:
Ksju [112]3 years ago
7 0

Answer:

J for impulse

t for time

F for force

formula is J=F×t

Explanation:

putting values in eqs after rearranging

we need to find force so

F=J ÷t

F=400÷15

=26.67

=27(rounded off)

27N is the Force applied.

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3 years ago
The reflective surface of a CD consists of spirals of equally spaced grooves. If you shine a laser pointer on a CD, each groove
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sin(A_{m}) = \frac{opposite}{Hypotenuse} \\sin(A_{m}) =\frac{1.1}{\sqrt{1.1^{2}+3^{2}}}

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3 years ago
An electrician finds that a 1 m length of a certain type of wire has a resistance of 0.24 Ω . What is the total resistance of th
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5 0
3 years ago
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