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nirvana33 [79]
3 years ago
8

Read through the scenarios below and calculate the predicted change in kinetic energy of the object compared to a 100 kg ball tr

aveling at 5 m/s. A 1,000 kg ball traveling at 5 m/s would have kinetic energy. A 10 kg ball traveling at 5 m/s would have kinetic energy. A 100 kg person falling at 5 m/s would have kinetic energy.
Physics
2 answers:
sashaice [31]3 years ago
4 0

Okay, first off, the formula for Kinetic Energy is:

<em>KE = 1/2(m)(v)^2</em>

<em>m = mass</em>

<em>v = velcoity (m/s)</em>


Using this formula, we can then calculate the kinetic energy in each scenario:

1) KE = 1/2(100)(5)^2 = 1,250 J

2) KE = 1/2(1000)(5)^2 = 12,500 J

3) KE = 1/2(10)(5)^2 = 125 J

4) KE = 1/2(100)(5)^2 = 1,250 J

gregori [183]3 years ago
3 0

Answer:

A 1,000 kg ball traveling at 5 m/s would have <u>10 times more</u> kinetic energy.

A 10 kg ball traveling at 5 m/s would have <u>10 times less</u> kinetic energy.

A 100 kg person falling at 5 m/s would <u>have the same</u> kinetic energy.

Explanation:

Edg 2020

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Answer:

A block of mass M = 5 kg is resting on a rough horizontal surface for which the coefficient of friction is 0.2. When a force F = 40N is applied, the acceleration of the block will be then (g=10ms

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Mass of the block=5kg

Coeffecient of friction=0.2

external applied force, F=40N

The angle at which the force is applied=30degree

So the horizontal component of force=Fcos30=40×

23 =20 3 N

While the uertical component of the force acting in upward direction=Fsin30=40× 21

​ =20N

The normal reaction from the surface (N)=mg−Fsin30=50−20=30N

So the ualue of limiting friction=μN=0.2×30=6N

Hence the net horizontal force on the block=Fcos30=μN=20

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​

N−6N=28.64N

The horizontal acceleration of the block=

m

Fcos30−μN = 528.64

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8 0
3 years ago
Which of the following is required for work to be done on an object?
ad-work [718]
I think that in order for work to be done, the object must move in the direction of the force and move over a distance.
7 0
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Listed following is a set of statements describing individual stars or characteristics of stars. Match these to the appropriate
Oksana_A [137]

Answer:

Red giant or super giant → very cool but very luminous

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Main sequence →The majority of stars in our galaxy

                        → Sun, for example

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White dwarfs → very hot but very dim

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Explanation:

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When the stars run out of their fuel that is hydrogen for the nuclear fusion reactions then they convert into Giant stars.That's why they are very cool. Giant stars have the larger radius and luminosity then the main sequence stars.

Main Sequence:

Stars are called main sequence stars when their core temperature reaches up to 10 million kelvin and their start the nuclear fusion reactions of hydrogen into helium in the core of the star. That is why they are very hot and luminous. For example sun is known as to be in the stage of main sequence as the nuclear fusion reactions are happening in its core.

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using the kinematic equation Vf= Vi + at

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podryga [215]

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4 0
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