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nirvana33 [79]
3 years ago
8

Read through the scenarios below and calculate the predicted change in kinetic energy of the object compared to a 100 kg ball tr

aveling at 5 m/s. A 1,000 kg ball traveling at 5 m/s would have kinetic energy. A 10 kg ball traveling at 5 m/s would have kinetic energy. A 100 kg person falling at 5 m/s would have kinetic energy.
Physics
2 answers:
sashaice [31]3 years ago
4 0

Okay, first off, the formula for Kinetic Energy is:

<em>KE = 1/2(m)(v)^2</em>

<em>m = mass</em>

<em>v = velcoity (m/s)</em>


Using this formula, we can then calculate the kinetic energy in each scenario:

1) KE = 1/2(100)(5)^2 = 1,250 J

2) KE = 1/2(1000)(5)^2 = 12,500 J

3) KE = 1/2(10)(5)^2 = 125 J

4) KE = 1/2(100)(5)^2 = 1,250 J

gregori [183]3 years ago
3 0

Answer:

A 1,000 kg ball traveling at 5 m/s would have <u>10 times more</u> kinetic energy.

A 10 kg ball traveling at 5 m/s would have <u>10 times less</u> kinetic energy.

A 100 kg person falling at 5 m/s would <u>have the same</u> kinetic energy.

Explanation:

Edg 2020

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olga nikolaevna [1]
The answer would be 6 because 2.0x3= 6

(newton’s 2nd law)

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4 0
2 years ago
What is the force of an object with a mass of 30 kg that is free falling?
disa [49]

Answer:

F = 294.3 [N]

Explanation:

To solve this problem we must use Newton's second law which tells us that force is equal to the product of mass by acceleration. It is this particular case the acceleration is due to the gravitational acceleration since the body is in free fall.

Therefore we have:

F = m*g

where:

F  = force [N]

m = mass = 30 [kg]

g = gravity acceleration = 9.81 [m/s^2]

F = 30*9.81

F = 294.3 [N]

4 0
3 years ago
What is a wave coming into a barrier
3241004551 [841]
A wave looses its power as it comes to shore because it gets less deeper every second it gets closer to shore
6 0
2 years ago
a man hikes 6.6 km north along a straight path with an average velocity of 4.2 km/h to the north. he rest at a bench for 15 min.
SSSSS [86.1K]

Answer:

2.6h

Explanation:

I attached the image below of the work hope you can see it. Hope this helps!

6 0
2 years ago
The distance, x, covered by a particle in time, t, is given as x=a +bc+ct^2 +dt^3
Sav [38]

Answer:

a has units of distance

b  has units of distance over time

c  has units of distance over time^2

d has units of distance over time^3

Explanation:

Since the expression for the distance is:

x = a+b\,t+c\,t^2+d\,t^3

then:

a has units of distance

b  has units of distance over time

c  has units of distance over time^2

d has units of distance over time^3

because we are supposed to be able to add all of the terms and get a distance.  So the products on each term that contains factors of time (t) should be cancelling those time units with units in the denominator of the multiplicative constant s that accompany them.

6 0
2 years ago
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