1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nirvana33 [79]
3 years ago
8

Read through the scenarios below and calculate the predicted change in kinetic energy of the object compared to a 100 kg ball tr

aveling at 5 m/s. A 1,000 kg ball traveling at 5 m/s would have kinetic energy. A 10 kg ball traveling at 5 m/s would have kinetic energy. A 100 kg person falling at 5 m/s would have kinetic energy.
Physics
2 answers:
sashaice [31]3 years ago
4 0

Okay, first off, the formula for Kinetic Energy is:

<em>KE = 1/2(m)(v)^2</em>

<em>m = mass</em>

<em>v = velcoity (m/s)</em>


Using this formula, we can then calculate the kinetic energy in each scenario:

1) KE = 1/2(100)(5)^2 = 1,250 J

2) KE = 1/2(1000)(5)^2 = 12,500 J

3) KE = 1/2(10)(5)^2 = 125 J

4) KE = 1/2(100)(5)^2 = 1,250 J

gregori [183]3 years ago
3 0

Answer:

A 1,000 kg ball traveling at 5 m/s would have <u>10 times more</u> kinetic energy.

A 10 kg ball traveling at 5 m/s would have <u>10 times less</u> kinetic energy.

A 100 kg person falling at 5 m/s would <u>have the same</u> kinetic energy.

Explanation:

Edg 2020

You might be interested in
Question 17 options:A 71.8 kg man goes from an area where the acceleration due to gravity is 9.79 m/s2 to an area where the acce
DerKrebs [107]
Mass doesn't change, no matter where you take it.
Your first impression of ' 0 ' is totally correct.
4 0
3 years ago
Rubric for Grading O Activity3. Answer me! Directions: Compare and contrast the scientific method in philosophy and in science.
emmasim [6.3K]
Yeah yeah I just got a hold of you and I saw that you were doing a good job and I thought you were doing a good job and I thought you were doing a good job and I thought you were doing a good job and I thought you were doing a good job and I thought you were doing a good job and I thought you were doing a good job and I thought you were doing a good job and I thought you were doing a good job and I thought you were doing a good job and I thought you were doing a good job and I thought you were doing a good job.
7 0
3 years ago
what equastion do you use to solve Riders in a carnival ride stand with their backs against the wall of a circular room of diame
Hitman42 [59]

Answer:

μsmín = 0.1

Explanation:

  • There are three external forces acting on the riders, two in the vertical direction that oppose each other, the force due to gravity (which we call weight) and the friction force.
  • This friction force has a maximum value, that can be written as follows:

       F_{frmax} = \mu_{s} *F_{n} (1)

       where  μs is the coefficient of static friction, and Fn is the normal force,

       perpendicular to the wall and aiming to the center of rotation.

  • This force is the only force acting in the horizontal direction, but, at the same time, is the force that keeps the riders rotating, which is the centripetal force.
  • This force has the following general expression:

       F_{c} =  m* \omega^{2} * r (2)

       where ω is the angular velocity of the riders, and r the distance to the

      center of rotation (the  radius of the circle), and m the mass of the

      riders.

      Since Fc is actually Fn, we can replace the right side of (2) in (1), as

      follows:

     F_{frmax} = m* \mu_{s} * \omega^{2} * r (3)

  • When the riders are on the verge of sliding down, this force must be equal to the weight Fg, so we can write the following equation:

       m* g = m* \mu_{smin} * \omega^{2} * r (4)

  • (The coefficient of static friction is the minimum possible, due to any value less than it would cause the riders to slide down)
  • Cancelling the masses on both sides of (4), we get:

       g = \mu_{smin} * \omega^{2} * r (5)

  • Prior to solve (5) we need to convert ω from rev/min to rad/sec, as follows:

      60 rev/min * \frac{2*\pi rad}{1 rev} *\frac{1min}{60 sec} =6.28 rad/sec (6)

  • Replacing by the givens in (5), we can solve for μsmín, as follows:

       \mu_{smin} = \frac{g}{\omega^{2} *r}  = \frac{9.8m/s2}{(6.28rad/sec)^{2} *2.5 m} =0.1 (7)

5 0
2 years ago
Distance meters Time (seconds) Trial Tria 2 Trials Average 3 053 059 0.52 055 6 106 719 104 Uning the values trom the data table
kumpel [21]
Jsisisusuagahannananana this is worth 22 points g that’s crazy 25
5 0
2 years ago
6- A metal block measures 10 cm x 2 cm x 2 cm. what is its volume? how many blocks each
zalisa [80]
You need 5 blocks of the smaller object to contain the same amount of volume of the bigger object

3 0
3 years ago
Other questions:
  • Answer the question below. Use the rubric in the materials for help if needed. Use details to support your response.
    12·1 answer
  • 1. The activation energy to form interstitial carbon in iron at room temperature is around 0.77 eV, and in vanadium at room temp
    7·1 answer
  • What's wrong with the following statement? “The racing car turns around
    11·1 answer
  • Rosa is riding her bike at 15 mph toward school. Select all of the following statements that correct describe her motion.
    6·2 answers
  • slader A baseball player slides to a stop on level ground. Using energy consideration, calculate the distance the 65 kg baseball
    8·1 answer
  • Denisty is found by what equation
    9·2 answers
  • ________________ is the measure of the quantity of the magnetism being the total number of magnetic lines of force passing throu
    9·1 answer
  • The time it takes for a dragster to cross the finish line is unknown. The dragster accelerates from rest at 26 m/s2 for a quarte
    14·1 answer
  • What are some examples of non-inertial reference frames?
    8·1 answer
  • In a parallel circuit, what’s happens to the current through each resistor when the voltage is doubled?
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!