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2 years ago

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A function that assigns a numerical value to each outcome of an experiment is called

1 answer:

kozerog [31]2 years ago

8 0

Random variable

Explanation:

A function that assigns a numerical value to each outcome of an experiment is described as a random variable. Random variables helps to determine the outcome of a random event.

Example of a random event is tossing of die, casting of a coin.
Random variables ascribe numerical values to the outcome of an experiment.
They are often used in probability to determine the extent of the certainty of an experimental procedure.

Learn more:

Probability brainly.com/question/1637111

#learnwithBrainly

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What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 55.0 nC placed between q1

notka56 [123]

Complete Question

Part of the question is shown on the first uploaded image

The rest of the question

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3 = 55.0 nC placed between q1 and q2 at x3 = -1.220 m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures.

Answer:

The net force exerted on the third charge is $F_{net}= 3.22*10^{-5} \ J$

Explanation:

From the question we are told that

The third charge is $q_3 = 55 nC = 55 *10^{-9} C$

The position of the third charge is $x = -1.220 \ m$

The first charge is $q_1 = -16 nC = -16 *10^{-9} \ C$

The position of the first charge is $x_1 = -1.650m$

The second charge is $q_2 = 32 nC = 32 *10^{-9} C$

The position of the second charge is $x_2 = 0 \ m$

The distance between the first and the third charge is

$d_{1-3} = -1.650 -(-1.220)$

$d_{1-3} = -0.43 \ m$

The force exerted on the third charge by the first is

$F_{1-3} = \frac{k q_1 q_3}{d_{1-3}^2}$

Where k is the coulomb's constant with a value $9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.$

substituting values

$F_{1-3} = \frac{9*10^{9}* 16 *10^{-9} * (55*10^{-9})}{(-0.43)^2}$

$F_{1-3} = 4.28 *10^{-5} \ N$

The distance between the second and the third charge is

$d_{2-3} = 0- (-1.22)$

$d_{2-3} =1.220 \ m$

The force exerted on the third charge by the first is mathematically evaluated as

$F_{2-3} = \frac{k q_2 q_3}{d_{2-3}^2}$

substituting values

$F_{2-3} = \frac{9*10^{9} * (32*10^{-9}) *(55*10^{-9})}{(1.220)^2}$

$F_{2-3} = 1.06*10^{-5} N$

The net force is

$F_{net} = F_{1-3} -F_{2-3}$

substituting values

$F_{net} = 4.28 *10^{-5} - 1.06*10^{-5}$

$F_{net}= 3.22*10^{-5} \ J$

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If you adjust the brightness of a light until it matches the intensity of sourness of the taste of a lemon, you are engaging in

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Unrestricted Submarine Warfare

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3 years ago

A car of mass 1600 kg can just be lifted what is the least force that the electronicmagnet must use to lift the car ?

Mkey [24]

The car's mass is 1600 kg.

Its weight is (mass) x (gravity).

On Earth, that's (1600 kg) x (9.8 m/s²) = 15,680 Newtons.

At the moment, that's the only force acting on the car, directed downward and provided by gravity.

If you want to lift the car, then the net force has to be directed upward, and must either exactly cancel or exceed the force of gravity.

So the minimum force required to lift the car is <em>15,680 Newtons</em>, directed vertically upward.

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A heat engine uses thermal energy that flows from a heat source with a temperature of 325 K to a cold sink, which has a temperat

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The answer is "58.5"

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An object can have forces acting upon it, but might not accelerate<br><br> True<br> or<br> False?

vivado [14]

Answer:

true

Explanation:

if you apply force to the top of a square it will not move

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