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bazaltina [42]
1 year ago
13

How many moles of solute would be dissolved in .500 kg of solvent to make a 2.50 molal NaOH solution?

Chemistry
1 answer:
Tom [10]1 year ago
3 0

Molality is a measure of concentration that relates the moles of solute to the kilograms of solvent, it is described by the following equation:

Molality=\frac{molSolute}{kgSolvent}

We are given the molality(2.50m) and kilograms of solvent(0.500kg), so we solve for moles of solute from the equation:

molSolute=Molality\times kgSolvent\begin{gathered} molSolute=2.50m\times0.500kg \\ molSolute=1.25molSolute \end{gathered}

To make a 2.50molal NaOH solution would be needed 1.25moles of solute

Answer: 1.25 moles

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Answer:Cell reaction is going forward.

Explanation:

For any chemical reaction to be spontaneous or to move in forward direction the ΔG ,the Gibbs free energy must be negative.

The cell potential of a battery is positive for a spontaneous reaction, so for a battery to give output its cell potential must be positive.

Thermodynamics and electro-chemistry are related in the following manner:

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so from the above equation ΔG would only be negative when E cell that is the cell potential is positive.

For a battery which is being used its cell potential is positive and hence the ΔG would be negative. So the cell reaction occurring would be in forward direction as ΔG is negative.

when the cell potential Ecell is 0 then ΔG is also zero then the reaction occurring in battery would be at equilibrium.

When the cell potential Ecell is - then ΔG is positive and the reaction would be occurring backwards.

3 0
3 years ago
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3 years ago
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If you combine 320.0 ml of water at 25.00 °c and 120.0 ml of water at 95.00 °c, what is the final temperature of the mixture? us
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Now, the heat is proportional to the mass, the specific heat and the temperature difference. The specific heat does not matter since all is water, it will cancel out:

m_1 * c_H20 * ( T_final - T_1 ) = -m_2 * c_H20 * ( T_final - T_2)

Notice the minus, because one wins the heat of the one who loses it. In this way both sides have the same sign:

m_1*(T_final - T_1)=-m_2*(T_final-T_2), or after some simple algebra:

T_final = (m_1 * T_1 + m_2 * T_2 )/(m_1+m_2),

which looks like an arithmetic mean, and one could have gone for this, but the above shows all the work. Notice that if T_1=T_2, T_final=T_1 always, which makes sense.

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8 0
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3- Multiply by 100 to get the error percentage:
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