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Zanzabum
1 year ago
14

you and your roommate are riding on a large carousel. you are standing near the center. your roommate is standing near the outsi

de edge. who has the greatest angular velocity?
Physics
1 answer:
spayn [35]1 year ago
6 0

You and your friends are revolving at the same speed. As a result, your friend and you both have the same angular velocity.

Now that we have the formula for linear velocity—V = omega—we can move on to the following section and draw the conclusion that if the relationship between and grows, so will we.

From here, we may also infer that the radius is larger in this instance because you are close to the right edge. Since you and your friend have different linear velocities and you have the higher linear velocity. If you've ever actually been on a merry-go-round, you already know that being on the edge is considerably more enjoyable rotation than being in the centre.

However, there is a similarity between the two people who are moving about. In the same amount of time, they will each cover the same rotation. The term "angular velocity" refers to a speed that measures the angle of rotation over a specified period of time.

To know more about velocity click on the link:

brainly.com/question/18084516

#SPJ4

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A proton is propelled at 4×106 m/s perpendicular to a uniform magnetic field. 1) If it experiences a magnetic force of 4.8×10−13
tia_tia [17]

Answer:

B = 0.75 T

Explanation:

As we know that the force on a moving charge in magnetic field is given by the formula

F = qvB

here we have

B = \frac{F}{qv}

here we know that

F = 4.8 \times 10^{-13} N

q = 1.6 \times 10^{-19} C

v = 4 \times 10^6 m/s

now from above equation we have

B = \frac{4.8 \times 10^{-13}}{(1.6 \times 10^{-19})(4 \times 10^6)}

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8 0
4 years ago
The shortstop plays between first and second base.<br> true or false
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3 years ago
Under which set of circumstances will the pressure of a gas DEFINITELY increase?
malfutka [58]
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4 years ago
How much kinetic energy does a system containing 3 moles of an ideal gas at 300 K possess? What is the heat capacity at constant
ElenaW [278]

Answer:

1. K.E = 11.2239 kJ ≈ 11.224 kJ

2. C_{V} = 37.413 JK^{- 1}

3. Q = 10.7749 kJ

Solution:

Now, the kinetic energy of an ideal gas per mole is given by:

K.E = \frac{3}{2}mRT

where

m = no. of moles = 3

R = Rydberg's constant = 8.314 J/mol.K

Temperature, T = 300 K

Therefore,

K.E = \frac{3}{2}\times 3\times 8.314\times 300

K.E = 11223.9 J = 11.2239 kJ ≈ 11.224 kJ

Now,

The heat capacity at constant volume is:

C_{V} = \frac{3}{2}mR

C_{V} = \frac{3}{2}\times 3\times 8.314 = 37.413 JK^{- 1}

Now,

Required heat transfer to raise the temperature by 15^{\circ} is:

Q = C_{V}\Delta T

\Delta T = 15^{\circ} = 273 + 15 = 288 K

Q = 37.413\times 288 = 10774.9 J = 10.7749 kJ

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Answer:

d

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