Answer:
10 N
Explanation:
While many people would like to simply add the forces from each end to get a total force, this is fundamentally incorrect.
MIGHT BE TOTALLY WRONG
Answer:
354 m/s
Explanation:
For the second overtune (Third harmonic) of an open pipe,
λ = 2L/3................................ Equation 1
Where L = Length of the open pipe, λ = Wave length.
Given: L = 1.75 m.
Substitute into equation 1
λ = 2(1.75)/3
λ = 1.17 m.
From the question,
V = λf.......................... Equation 2
V = speed of sound in the room, f = frequency
Given: f = 303 Hz.
Substitute into equation 2
V = 1.17(303)
V = 353.5
V ≈ 354 m/s
Hence the right answer is 354 m/s
Tendon Sheath - is a specialized bursa that wraps around a tendon to reduce friction.
<h3>What is Tendon Sheath ?</h3>
Tendon Sheath is a thin layer of tissue, surrounds each tendon in our body. The tendon sheath can also be called synovial lining or fibrous sheath. Tendon sheaths help to protect tendons from abrasive damage as they move.
Connection between Bursa and Tendon Sheath : Bursae are small fluid-filled sacs that can lie under a tendon, cushioning the tendon and protecting it from the injury. Bursae also provides an extra cushioning to adjacent structures that otherwise might rub against each other, which will cause wear and tear ( example, between a bone and a ligament ) .
So, lastly we can say that Tendon Sheath is the specialized bursa that wraps around a tendon to reduce friction.
To know more about Tendon Sheath please click here : brainly.com/question/17087116
#SPJ4
The force is opposite to the displacement
Answer:
The smallest radius will be four (4) times the initial radius
Explanation:
The car maintains a constant angular speed. According to Newton's Second Law F = m a
1. 
2. 
Replacing 2 in 1
3. 
Where:
Fr= Frictional force
Rp= Initial Radius
An= Centripetal Acceleration
M= Mass
V= Velocity
Also we have that:
4. 
μ= Coefficient of friction between the car and the surface
M= Mass
W= Weight
G= Gravity
r is cleared from equation 3
5. 
Replacing 4 in 5
6. 
Simplifying
7. 
Now we have a new velocity equal to twice the initial velocity, We replace it by 2v in equation 7
8. 
Computing
9. 
Replacing 5 in 9
