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Reil [10]
1 year ago
13

Which scatterplot shows the correct division for using the Divide-Center of Data method to draw the trend line?

Chemistry
1 answer:
nlexa [21]1 year ago
5 0

The appropriate scatter plot that depicts the correct division for using Divide center to draw trend line is the plot D.

<h3>What are Scatter plots?</h3>

Scatter plots are used to show how much one variable affects another by plotting data points on a horizontal and vertical axis. Each row in the data table is represented by a marker, the position of which is determined by the values of the columns set on the X and Y axes. Scatter plots are graphs that show the relationship of two variables in a data set. It is a two-dimensional plane or a Cartesian system that represents data points.

In order to draw a trend line correctly, divide the points using the divide center method. The dividing vertical line must be drawn at the midpoint (a position where the number of data points to the left and right of the vertical line is equal).

Only option D has a vertical line dividing the 6 data points into two equal portions when the options are evaluated based on this condition.

The diagram is attached.

Learn more about scatter plot on:

brainly.com/question/24307855

#SPJ1

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Answer:

false

Explanation:

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3 years ago
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There are two stereoisomers of 1-tert-butyl-4-chloro-cyclohexane. One of these isomers reacts with sodium ethoxide in an E2 reac
Naily [24]

Answer:

Explanation:

Answer:

<u>cis-</u>isomer reacts faster

Explanation:

The missing diagrams in the question are attached in the first image below and the isomers that react faster are shown in the second image attached.

The <u>cis-</u>isomer quickly follows E2 reaction due to the fact that it is locked in a chair conformation whereby chlorine dominates an <u>axial </u>position, as displayed in drawing <u>C </u>as well as the leaving group <u>Cl</u> which is antiperiplanar to a beta proton.

Due to the bulkiness of tert-butyl, the<u> trans-</u>isomer is Basically trapped in a chair configuration, with chlorine occupying an <u>equatorial</u> position as displayed in drawing <u>A</u> below, thus leaving the group isn't antiperiplanar to a beta proton.

Tert butyl favors an equatorial position due to its bulkiness. This makes the Cl to assume an axial position in an isomer

The difference:

From the second image attached below, in the first diagram(1):

Suppose H is antiperiplanar, C-H bond electrons reach antibonding orbitals of C-Cl, assisting in the breakdown of the C-Cl bond and therefore speeding up the process.

From the second diagram(2) in the second image:

Unless Cl is in the axial position would it have β-hydrogen in the antiperiplanar position. Because tert-butyl prefers equatorial location, the Cl occupies equatorial position in the trans isomer.

As a result, the reaction is slower and there is no β-hydrogen antiperiplanar to Cl.

8 0
3 years ago
Match each type of titration to its ph at the equivalence point for solutions at 25 ∘c. drag each item to the appropriate bin. v
sdas [7]
The complete question;
Match each type of titration to its pH at the equivalence point.
Weak acid, strong base
Strong acid, strong base
Weak base, strong acid

pH less than 7
pH equal to 7
<span>pH greater than 7
</span>Answer:
weak acid, strong base - pH greater than 7
Strong acid, strong base - pH equal to 7
Weak base, strong acid - pH less than 7
Strong acids dissociate completely to give out H⁺ ions. 
Strong bases dissociate completely to give out OH⁻ ions.
When strong acids and strong bases are mixed the dissociated H⁺ and OH⁻ ions  react and neutralise each other, making the solution neutral.
Weak acids cannot completely dissociate, only a fraction of H⁺ ions are dissociated. Same applies for weak bases.
When weak acid and strong base is mixed, whilst the strong acid completely dissociates, weak base only partially dissociates. Therefore the amount of H⁺ ions is greater than OH⁻ ions, overall pH is more acidic, hence less than 7.
When strong base and weak acid are mixed, strong base completely dissociates giving OH⁻ ions and weak acid only partially dissociates, therefore amount of OH⁻ ions is greater than H⁺ ions, more basic hence pH is greater than 7.

5 0
3 years ago
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Then, the Cu(H₂O)₆²⁺ ions will absorb the orange color, and reflect the blue one, and the solution will be blue. The beta-carotene will absorb the blue color and will reflect the orange, so the solution will be orange.

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CO2+H2O= C6H12O6+O2+H2O

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