Organism, population, community, ecosystem, and biome
Answer:
2726.85 °C
Explanation:
Given data:
Initial pressure = 565 torr
Initial temperature = 27°C
Final temperature = ?
Final pressure = 5650 torr
Solution:
Initial temperature = 27°C (27+273 = 300 K)
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
T₂ = P₂T₁ /P₁
T₂ = 5650 torr × 300 K / 565 torr
T₂ = 1695000 torr. K /565 torr
T₂
= 3000 K
Kelvin to degree Celsius:
3000 K - 273.15 = 2726.85 °C
The grams of glucose are needed to prepare 400g of a 2.00%(m/m) glucose solution g is calculated as below
=% m/m =mass of the solute/mass of the solution x100
let mass of solute be represented by y
mass of solution = 400 g
% (m/m) = 2% = 2/100
grams of glucose is therefore =2/100 = y/400
by cross multiplication
100y = 800
divide both side by 100
y= 8.0 grams
In order for carbon to be stable and have 8 electrons, it must make 4 total covalent bonds.
In prefer for oxygen to be stable and have 8 electrons, it must make 2 covalent bonds.
So, we can deduce that CO2 looks like this:
O=C=O
This molecule has two double bonds.
Pssst...Can I get a brainliest?
Answer:
, the solution is basic
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7.
![pH=-\log [H_3O^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH_3O%5E%2B%5D)
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
Putting in the values:
![pOH=-\log[5.5\times 10^{-5}]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5B5.5%5Ctimes%2010%5E%7B-5%7D%5D)



![9.8=-\log [H_3O^+]](https://tex.z-dn.net/?f=9.8%3D-%5Clog%20%5BH_3O%5E%2B%5D)
![[H_3O^+]=1.6\times 10^{-10}M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D1.6%5Ctimes%2010%5E%7B-10%7DM)
As pH is more than 7, the solution is basic