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o-na [289]
3 years ago
15

Which type of data have elements in common but do not fit into rigid rows and columns in a table?.

Chemistry
1 answer:
Talja [164]3 years ago
6 0

Answer: Semi-structured data is a type of data that has some consistent and definite characteristics. It does not confine into a rigid structure such as that needed for relational databases that which is why  it will not fit into row and columns in a table .

Explanation:

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What the difference between chlorine and non chlorine bleach?
padilas [110]
The basic difference between chlorine and blench is that a natural element, while bleach is a solution of many elements.

Hope this help..
5 0
3 years ago
Using the molecular weight (258 g/mol) determine the amount of mmol of (3S)-2,2,- dibromo-3,4-dimethylpentane required.
Varvara68 [4.7K]

The question is incomplete, the complete question is;

With all of this data in hand, we can now set up our reaction. To begin we are going to use 0.7 g of (35)-2.2-dibromo-3,4-dimethylpentane. Question #7: Using the molecular weight (258 g/mol) determine the amount of mmol of (3S)-2,2,- dibromo-3,4-dimethylpentane required. Round to the tenths place

Answer:

2.70 mmols

Explanation:

Given that;

Mass of (3S)-2,2,- dibromo-3,4-dimethylpentane = 0.7 g

Molar mass of (3S)-2,2,- dibromo-3,4-dimethylpentane = 258 g/mol

From,

Number of moles = mass/molar mass

Number of moles of (3S)-2,2,- dibromo-3,4-dimethylpentane = 0.7g/258 g/mol = 2.7 ×10^-3 moles

Therefore;

Number of moles of (3S)-2,2,- dibromo-3,4-dimethylpentane = 2.70 mmols

8 0
4 years ago
Acids are a class of chemical compounds which produces ________? , ___? , in aqueous solution
Sloan [31]
Hydrogen ions,H+ ions??
6 0
3 years ago
33 grams of NH4NO3 will produce how many grams of water
Leni [432]

Answer:

66 grams

Explanation:

For every 1 gram of NH4NO3 equals 2 grams of water

8 0
4 years ago
The following information is given for ether, C2H5OC2H5, at 1atm: boiling point = 34.6 °C Hvap(34.6 °C) = 26.5 kJ/mol specific h
Likurg_2 [28]

Answer:

The heat is  H= -8.044KJ

Explanation:

From the question we are told that

   The pressure is  P = 1 \ atm

    The boiling point is  B_P  = 34^oC

     The heat of vaporization at 34°C is  = 26.5 kJ/mol

       The specific heat of the liquid is c_p = 2.32 J/g^oC

      The  mass is  m = 22.5g

  The no of moles of the sample of C_2 H_5OC_2H_5  is given as

               No \ mole (n)  = \frac{Mass \ of  \ sample }{Molar \ mass }

    The  Molar mass for C_2 H_5OC_2H_5  is a value = = 74.12 g/mol

Substituting the value into the above equation

          n  = \frac{22.5}{74.12}

                           = 0.30356 \ mol

      The heat H is mathematically as

                H  =- nH_{vap}

The negative sign show that the heat is for condensing

            H = 0.30356 * 26.5 *10^{3} J/mol

                H= -8.044KJ

                   

6 0
4 years ago
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