If you are using a thermometer, you are measuring the

The primary reason some parts of Earth are hotter than other parties because the hotter parts of Earth

Shtirlitz [24]

Answer: the core

Explanation:

6 0

3 years ago

A bottle of wine contains 12.8% ethanol by volume. The density of ethanol (CH3OH) is 0.789 g/cm. Calculate the concentratic etha

Scrat [10]

Answer : The mass percent of ethanol is, 10.38 % and the molality of ethanol is, 2.52 mole/kg

Explanation :

In wine, the solute and solvent are ethanol and water respectively.

Given :

12.8 % ethanol by volume means 12.8 mL ethanol present in 100 mL solution.

Volume of ethanol = 12.8 mL

Volume of solution = 100 mL

Volume of water = 100 - 12.8 = 87.2 mL

Density of ethanol = $0.789g/cm^3=0.789g/mL$

Density of water = 1 g/mL

Now we have to calculate the mass of ethanol and water.

$\text{Mass of ethanol}=\text{Density of ethanol}\times \text{Volume of ethanol}=0.789g/mL\times 12.8mL=10.1g$

and,

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/mL\times 87.2mL=87.2g$

Now we have to calculate the total mass of 100 mL of wine.

Total mass of 100 mL of wine = 10.1 + 87.2 = 97.3 g

Now we have to calculate the mass percent of ethanol.

$\text{Mass of percent of ethanol}=\frac{\text{Mass of ethanol}}{\text{Total mass of solution}}\times 100$

$\text{Mass of percent of ethanol}=\frac{10.1g}{97.3g}\times 100=10.38\%$

The mass percent of ethanol is, 10.38 %

Now we have to calculate the molality.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}$

Molar mass of ethanol = 46 g/mole

$Molality=\frac{10.1g\times 1000}{46g/mole\times 87.2g}=2.52mole/kg$

The molality of ethanol is, 2.52 mole/kg

6 0

3 years ago

What is the volume of NH3 produced in the following reaction when 3.0L of N2 reacts with 4.0L of H2?

trapecia [35]

Hey there !

Given the reaction:

N2 + 3 H2 = 2 NH3

At constant pressure and temperature ,volume is proporcional to moles:

Theoretical moles of N2 and H2 => 1:3

Theoretical volume of N2 and H2 => 1:3

Experimental volume of N2 and H2 => 3.0 L : 4.0 L

0.75 : 1 = 2.25 : 3

Since N2 is in excess reactant , H2 is the limiting reactant

Therefore:

volume of NH3 is 2/3 * Volume of H2

= 2/3 * 4.0 = 2.66 L

Hope that helps!

4 0

3 years ago

Read 2 more answers

Cesium-137 is part of the nuclear waste produced by uranium-235 fission. The half-life of cesium-137 is 30.2 years. How much tim

Aleonysh [2.5K]

Answer:

la primera va con la última

5 0

3 years ago

Select the correct identity of glacial acetic acid.

Lemur [1.5K]

Answer:

It is pure, anhydrous acetic acid is the correct answer.

Explanation:

Glacial acetic acid contains very less water that the reason it is called anhydrous.

Glacial acetic acid is a colorless, clear liquid and corrosive.

The glacial acetic acid in the diluted form used in vegetables and food preservation,flavoring in the slice, sausage, canned fruits and also it used to treat the bacteria and fungal infections.

6 0

3 years ago