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Mariana [72]
3 years ago
13

PLEASE HURRY HELP ME THIS IS ENGLISH!!! Mr. Tushman looked right at me and smiled and nodded. He put his hand out for me to shak

e. "Hi, August," he said, totally normally. "It's a pleasure to meet you." "Hi," I mumbled, dropping my hand into his hand while I looked down at his feet. He was wearing red Adidas. —Wonder R.J. Palacio.
What text details help you infer that August is nervous about meeting Mr. Tushman? Check all that apply.


A.) Mr. Tushman looks right at August and smiles.


B.) Mr. Tushman says hello to August totally normally.


C.) August mumbles "hi" to Mr. Tushman.


D.) August shakes Mr. Tushman's hand.


E.) August looks down at Mr. Tushman's shoes.
Physics
2 answers:
sergeinik [125]3 years ago
7 0

Answer:

C and E makes the most sense

Explanation:

c. whenever someone mumbles its usually a sign of nervousness or shyness.

e. people lose eye contact when they are nervous.

kondaur [170]3 years ago
4 0

Answer:

The answers are C and E.

Explanation:

August shows he's nervous by mumbling and looking down, key factors that show nervousness.

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Mr. Bennet's class completed an investigation on magnetism. They found that most metals were attracted to magnets and plastics w
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A

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3 years ago
When the electron in a hydrogen atom moves from n = 6 to n = 1, light with a wavelength of ________ nm is emitted?
Oduvanchick [21]
First we find the energy level with the following formula, where a is the energy level, n1 is the final energy level, n2 is the starting energy level and r is Rydberg's constant in Joules
a = r \times ( \frac{1}{n1}  -  \frac{1}{n2} )
We insert the values

a = 2.18 \times  {10}^{ - 18}  \times ( \frac{1}{ {1}^{2} } -  \frac{1}{ {6}^{2} }  )
= 2.12 \times {10}^{ - 18}
The wavelength is found with this formula, where h is Planck's constant and c is the speed of light
wavelength =  \frac{h \times c}{a}
Finally we insert the values
\frac{6.626 \times  {10}^{ - 34}  \times 3 \times  {10}^{8} }{2.12 \times  {10}^{ - 18} }  = 9.376 \times  {10}^{ - 8}
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3 0
3 years ago
In a particular metal, the mobility of the mobile electrons is 0.0033 (m/s)/(N/C). At a particular moment, the electric field ev
Lapatulllka [165]

Answer:

the average drift speed of the mobile electrons in the metal is 1.089 x 10⁻⁴ m/s.

Explanation:

Given;

mobility of the mobile electrons in the metal, μ = 0.0033 (m/s)/(N/C)

the electric field strength inside the cube of the metal, E = 0.033 N/C

The average drift speed of the mobile electrons in the metal is calculated as;

v = μE

v =  0.0033 (m/s)/(N/C) x 0.033 N/C

v = 1.089 x 10⁻⁴ m/s.

Therefore, the average drift speed of the mobile electrons in the metal is 1.089 x 10⁻⁴ m/s.

6 0
3 years ago
Name one metal and one non-metal from the periodic table? <br><br> Y’all I need help<br> Thank you!
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Answer:

Zinc and Neon!

Explanation:

zinc is an element that is a transition metal and neon is a noble gas

8 0
3 years ago
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SVETLANKA909090 [29]

Answer:

the rates of rock formation are similar. i could be wrong tho.....

Explanation:

6 0
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