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Mariana [72]
3 years ago
13

PLEASE HURRY HELP ME THIS IS ENGLISH!!! Mr. Tushman looked right at me and smiled and nodded. He put his hand out for me to shak

e. "Hi, August," he said, totally normally. "It's a pleasure to meet you." "Hi," I mumbled, dropping my hand into his hand while I looked down at his feet. He was wearing red Adidas. —Wonder R.J. Palacio.
What text details help you infer that August is nervous about meeting Mr. Tushman? Check all that apply.


A.) Mr. Tushman looks right at August and smiles.


B.) Mr. Tushman says hello to August totally normally.


C.) August mumbles "hi" to Mr. Tushman.


D.) August shakes Mr. Tushman's hand.


E.) August looks down at Mr. Tushman's shoes.
Physics
2 answers:
sergeinik [125]3 years ago
7 0

Answer:

C and E makes the most sense

Explanation:

c. whenever someone mumbles its usually a sign of nervousness or shyness.

e. people lose eye contact when they are nervous.

kondaur [170]3 years ago
4 0

Answer:

The answers are C and E.

Explanation:

August shows he's nervous by mumbling and looking down, key factors that show nervousness.

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Answer:

Looks like <em>Trigonal Planar</em>

Explanation:

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7 0
3 years ago
An unstretched spring has a length of 10. centimeters. When the spring is stretched by a force of 16 newtons, its length is incr
Fed [463]

Answer:

The spring constant of this spring  is 200 N/m.

Explanation:

Given:

Original unstretched length of the spring (x₀) = 10 cm =0.10 m [1 cm =0.01 m]

Stretched length of the spring (x₁) = 18 cm = 0.18 cm

Force acting on the spring (F) = 16 N

Spring constant of the spring (k) = ?

First let us find the change in length of the spring or the elongation caused in the spring due to the applied force.

So, Change in length = Final length - Initial length

\Delta x = x_1-x_0=0.18-0.10=0.08\ m

Now, restoring force acting on the spring is directly related to its elongation or compression as:

F=k\Delta x

Rewriting in terms of 'k', we get:

k=\dfrac{F}{\Delta x}

Now, plug in the given values and solve for 'k'. This gives,

k=\frac{16\ N}{0.08\ m}\\\\k=200\ N/m

Therefore, the spring constant of this spring  is 200 N/m.

5 0
3 years ago
Two antennas located at points A and B are broadcasting radio waves of frequency 96.0 MHz, perfectly in phase with each other. T
earnstyle [38]

Answer:

a)   Δφ = 1.51 rad , b)  x = 21.17 m

Explanation:

This is an interference problem, as they indicate that the distance AP is on the x-axis the antennas must be on the y-axis, the phase difference is

          Δr /λ = Δfi / 2π

          Δfi = Δr /λ 2π

          Δr = r₂-r₁

let's look the distances

         r₁ = 57.0 m

We use Pythagoras' theorem for the other distance

         r₂ = √ (x² + y²)

         r₂ = √(57² + 9.3²)

         r₂ = 57.75 m

The  difference is

         Δr = 57.75 - 57.0

         Δr = 0.75 m

Let's look for the wavelength

        c =  λ f

          λ = c / f

          λ = 3 10⁸ / 96.0 10⁶

          λ = 3.12 m

Let's calculate

         Δφ = 0.75 / 3.12 2π

         Δφ = 1.51 rad

b) for destructive interference the path difference must be λ/2, the equation for destructive interference with φ = π remains

           Δr = (2n + 1) λ / 2

           

For the first interference n = 0

           Δr = λ / 2

           Δr = r₂ - r₁

We substitute the values

        √ (x² + y²) - x = 3.12 / 2

Let's solve for distance x

          √ (x² + y²) = 1.56 + x

          x² + y² = (1.56 + x)²

          x² + y² = 1.56² + 2 1.56 x + x²

          y2 = 20.4336 +3.12 x

          x = (y² -20.4336) /3.12

          x = (9.3² -20.4336) /3.12

          x = 21.17 m

This is the distance for the first minimum

6 0
3 years ago
Read 2 more answers
What does it mean if a paint sample "matches" a known sample from a vehicle? Does this indicate the same source? Why or why not?
Mandarinka [93]
It wouldn't indicate the same source if the paint was from a different place. If the paint was the same brand and color it would be but if not then no
4 0
3 years ago
Two positive charges of 20 micro coulomb and 100 micro coulomb and the distance between them is 150cm.What will be the electrica
Roman55 [17]

Answer:

0.8 N

Explanation:

From coulomb's law,

Formula:

F = kqq'/r²........................ Equation 1

Where F = Force of repulsion, k = coulomb's constant, q = first positive charge, q' = second positive charge, r = distance between the charge.

Given: q = 20 μC = 20×10⁻⁶ C, q' = 100 μC = 100×10⁻⁶ C, r = 150 cm = 1.5 m.

Constant:  k = 9×10⁹ Nm²/C²

Substitute these values into equation 1

F = (20×10⁻⁶ )( 100×10⁻⁶)(9×10⁹)/1.5²

F = 1800×10⁻³/2.25

F = 1.8/2.25

F = 0.8 N

3 0
3 years ago
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