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Blababa [14]
1 year ago
9

Does anyone know the minim value of the function f(x) =2x^2 -4x -6?. I’m online due to my quarantine and am looking for extra he

lp. Here is a picture. Nvm :/

Mathematics
1 answer:
navik [9.2K]1 year ago
4 0

Answer:

f(x) = - 8

Explanation:

The given function is

f(x) =2x^2 -4x -6

The first step is to find the derivative of the function. Recall, if

y = ax^b

y' = abx^(b - 1)

Thus,

f'(x) = 4x - 4

We would equate f'(x) to zero and solve for x. We have

4x - 4 = 0

4x = 4

x = 4/4

x = 1

We would substitute x = 1 into the original function and solve for f(x) or y. It becomes

f(1) =2(1)^2 -4(1) - 6 = 2 - 4 - 6

f(1) = - 8

Thus, the minimum value is f(x) = - 8

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Answer:

∠U = 56.4

Step-by-step explanation:

We can use trigonometric functions to solve this

Here we are given the opposite side of ∠U as well as the adjacent side.

When dealing with the adjacent and opposite side we use sin

Sin = Opposite side / Adjacent side

Opp = 5 and adj = 6

So

Sin(U) = 5/6

* take the inverse sine of both sides *

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arcsin(5/6) = 56.4 *( rounded to the nearest tenth )

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Please help me ASAP?!!
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Answer:

(0,-5) and (-4,3)

Step-by-step explanation:

The given equations are

\left \{ {{x^2+y^2=25} \atop {2x+y=-5}} \right.

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Substitute into the first equation;

x^2+(-2x-5)^2=25

Expand:

x^2+4x^2+20x+25=25

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