Question

A guitar's steel string vibrates (see Fig. 31.5). The component of magnetic field perpendicular to the area of a pickup coil nearby is given byB=50.0+3.20 sin 1046 πtwhere B is in milliteslas and t is in seconds. The circular pickup coil has 30 turns and radius 2.70mm. Find the emf induced in the coil as a function of time.

Answer 1

The emf induced in the coil as a function of time is 2.2 mV.

emf induced in the coil

The emf induced in the coil is calculated as follows;

emf = NAdB/dt

where;

• N is number of turn
• A is the area of the coil
• dB/dt is the change in magnetic field with time

A is area of the coil, A = πr² = π(2.7 x 10⁻³)² = 2.29 x 10⁻⁵ m².

dB/dt = 3.2cos(1046π) = 3.2

emf = (30 x 2.29 x 10⁻⁵ x 3.2) = 2.2 x 10⁻³ V

emf = 2.2 mV

Thus, the emf induced in the coil as a function of time is 2.2 mV.

Learn more about induced emf here: brainly.com/question/13744192

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