Providing subgoals for individuals helps them solve problems more quickly. True or False

Physics

2 answers:

zvonat [6]3 years ago

7 0

Answer: The given statement is true.

Explanation:

A small goal which is a part of and helpful in accomplishing a large goal is known as a subgoal.

Basically, a subgoal is a step-by-step process in which a bigger problem or aim is broken down into small manageable pieces that will lead us towards solving or accomplishing of goal.

For example, a student wants to achieve first position in his class. So, for this he started his preparation from the starting of the session and not a day or week before the exams.

Hence, we can conclude that the statement, providing subgoals for individuals helps them solve problems more quickly, is true.

trasher [3.6K]3 years ago

3 0

True because they can focus on small goals to eventually solve their big problems.

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Sliva [168]

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3 years ago

At a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienc

vaieri [72.5K]

Answer:

27.1 m/s

Explanation:

Given that at a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2.

Using third equation of motion,

V^2 = U^2 + 2aS

Since the car is decelerating, the final velocity V = 0

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0 = U^2 - 2 * 40.52 * 9.06

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U = 27.096

U = 27.1 m/s approximately

Therefore, the staff member can estimate for the original speed of the race car to be 27.1 m/s if it came to a stop during the skid

5 0

3 years ago

Initially a car accelerates at 2 m/s2 for x seconds. The car then travels at a velocity of -6 m/s for x seconds. If the car disp

Luda [366]

Answer:

The time travel is

t=8 s

Explanation:

$a= 2 \frac{m}{s^{2} } \\v=-6 \frac{m}{s} \\x=16m$

$x_{f}=x_{o}+v_{o}*t+\frac{1}{2} *a*t^{2}$

$x_{f}=0-6*t+\frac{1}{2} *2*t^{2}$

$t^{2}-6*t-16=0\\ using :\\\frac{-b+/-\sqrt{b^{2}-4*c*a } }{2} \\\frac{-(-6)+/-\sqrt{(-6)^{2}-4*(-16)*(1) } }{2}=\frac{3}{2} +/- \frac{10}{2} \\t_{1} = 2s \\t_{2} = 8s$