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raketka [301]
1 year ago
6

Determine the limiting reactant and calculate the number of grams of sulfur dioxide, so2, that can be formed when 27.3 g of meth

ane thiol, ch3sh, reacts with 38.6 g of oxygen, o2.
Chemistry
1 answer:
lyudmila [28]1 year ago
6 0

When Methane thiol, CH₃SH, reacts with O₂, 25.8 grams of Sulfur dioxide, SO₂ is formed and limiting reactant is Oxygen, O₂.

The balanced chemical reaction is:

<em>CH₃SH(g) + 3 O₂(g) → 2 H₂O(g) + CO₂(g) + SO₂(g)</em>

<em />

             Molecular weights:       Actual/given mass:

CH₃SH = 48.11 g/mol                    27.3 g      

O₂         = 32.01 g/mol                    38.6 g  

H₂O      = 18.01 g/mol            

CO₂      = 44.01 g/mol                  

SO₂       = 64.06 g/mol

Number of moles = <u>    Given mass     </u>

                                  Molecular mass

So,

moles of methane thiol = 27.3 ÷ 48.11= 0.56 moles

moles of oxygen = 32.01÷38.6 = 0.82 moles

From the reaction,

1 mole of CH₃SH reacts with 3 moles of O₂  to give 1 mole of SO₂

Thus, 0.56 moles of CH₃SH reacts to form 1 × 0.56 = 0.56 moles of SO₂

Mass of SO₂ produced is 0.56 × 64.06 g = 35.86 g

moles of SO₂ = 35.86 ÷ 64.06 = 0.55 moles

So,

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Answer:

Energy transfer takes place when energy moves from one place to another. … When energy in a battery is used to power an electronic device, chemical energy is transformed into electrical energy, which moves along wires. Three more ways energy can be transferred are through light, sound, and heat.

Explanation:

6 0
2 years ago
4. A salvage operator recovered coins believed to be gold. A sample weighed 385.000g and has a volume of 20.0mL. Were the coins
aleksley [76]

Answer:

Gold

Explanation:

We are given that

Mass of sample ,m=385 g

Volume ,V=20mL

We have to find the coin is gold or yellow brass.

We know that

Density=\frac{Mass}{volume}

Using the formula

Density=\frac{385}{20}g/mL

Density=19.25g/mL

Density\approx 19.3g/mL

Density of coin=19.3g/mL

Density of gold=19.3g/mL

Hence, the coin is gold.

5 0
3 years ago
5. A 5.00 g sample of an unknown substance was heated from 25.2 C to 55.1 degrees * C , and it required 133 to do so. Identify t
Leviafan [203]

Answer:

Aluminum

Explanation:

Given

T_1 = 25.2^oC

T_2 = 55.1^oC

m = 5.00g

\triangle Q= 133J

<em>See attachment for chart</em>

Required

Identify the unknown substance

To do this, we simply calculate the specific heat capacity from the given parameters using:

c = \frac{\triangle Q}{m\triangle T}

This gives:

c = \frac{\triangle Q}{m(T_2 - T_1)}

So, we have:

c = \frac{133J}{5.00g * (55.1C - 25.2C)}

c = \frac{133J}{5.00g * 29.9C}

c = \frac{133J}{149.5gC}

c = 0.89\ J/gC

From the attached chart, we have:

Al(s) = 0.89\ J/gC --- The specific heat capacity of Aluminum

<em>Hence, the unknown substance is Aluminum</em>

7 0
3 years ago
What is the electron configuration for Fe?
blsea [12.9K]
The answer is C) [Ar]4s2 3d6
5 0
3 years ago
Read 2 more answers
If I have 6 moles of a gas at a pressure of 3.4 atm and a volume of 10 liters, what
ch4aika [34]

Answer:

The temperature is 69.05 K.  

Explanation:

We have,

Number of moles are 6

Pressure is 3.4 atm and a volume of 10 liters.

It is required to find the temperature. It can be calculated using gas law equation. It says that,

PV=nRT

P is pressure

V is volume

n is number of moles

R is gas constant, R=0.082057\ L-atm/mol-K

T is temperature                

Plugging all the values we get :

T=\dfrac{PV}{nR}\\\\T=\dfrac{3.4\times 10}{6\times 0.082057}\\\\T=69.05\ K

So, the temperature is 69.05 K.  

8 0
3 years ago
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