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Alina [70]
2 years ago
5

Convert these temperatures to Celsius: a. 303 K d. 45 K

Chemistry
1 answer:
andre [41]2 years ago
8 0

303K − 273.15 = 29.85°C

45K − 273.15 = -228.1°C

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If 125 grams of Cu reacts 75 grams of HNO3, how many grams of Cu(NO3) form?
melisa1 [442]

Answer: 37.5grams of Cu(NO3)2

Cu(1mol) + 2HNO3(2mol) —> Cu(NO3)2 + H2

<em>125 grams of Cu(1mol) reacts with 75 grams of HNO3(2mol)</em>

<em><u>HNO3 is the limiting substance, therefore, 75 grams is the limiting quantity.</u></em>

<em>Therefore, 2mol of HNO3 forms 1mol of Cu(NO3)2</em>

<em>75 grams of HNO3 forms...75grams x 1mol/2mol = 37.5 grams of Cu(NO3)2</em>

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3 years ago
Select all that apply. Catalysts can save money by essentially lowering the:
k0ka [10]

Answer: Options (a) and (d) are the correct answer.

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A catalyst is the substance which helps in increasing the rate of reaction.

Activation energy is the minimum amount of energy required by reactants to start the reaction. On addition of catalyst, the path of reaction changes because the energy barrier gap reduces and hence, the activation energy also decreases.

In the absence of catalyst, we need to increase the temperature so that reaction can occur quickly.

Whereas on addition of catalyst, there is no need to increase the temperature as the catalyst itself is sufficient to increase the rate of reaction. As a result, temperature should be lowered when there is addition of catalyst in the reaction.

Thus, we can conclude that catalysts can save money by essentially lowering the activation energy and temperature required.


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Calculate the number of grams of Hydrogen required to produce 5.73 grams of water. 2H2+O2---&gt;2H2O 2 grams 0.636 grams 1.2 gra
rusak2 [61]

Explanation:

32

2H

2

+O

2

→2H

2

O

Molecular mass of H

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=2 g/mol

Molecular mass of O

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=32 g/mol

From the balanced chemical equation,

2×2=4 g of hydrogen requires 32 g of Oxygen to react completely

3 0
3 years ago
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