What is the correct name for CaS04? (a) calcium sulfoxide (b) calcium sulfite (c) calcium sulfur oxide (d) calcium sulfate (e) c
2 answers:
<u>Answer:</u> The name of is calcium sulfate.
<u>Explanation:</u>
An ionic compound is defined as the compound which is formed when electron gets transferred from one atom to another atom. These are usually formed when a metal reacts with a non-metal or a metal reacts with a polyatomic ion or a reaction between two polyatomic ions takes place.
is an ionic compound because calcium element is a metal and sulfate ion is a polyatomic ion. The bond formed between a metal and a non-metal is always ionic in nature.
The nomenclature of ionic compounds is given by:
- Positive ion is written first.
- The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
- In case of polyatomic ions, the name of the ion is written as such. <u>For Example:</u>
is named as hydroxide,
is named as sulfate and so on..
Hence, the name of is calcium sulfate.
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Answer:
4.96E-8 moles of Cu(OH)2
Explanation:
Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.
Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.
This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:
In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":
The expression for Kps is:
The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.
"s" is the soluble quantity of Cu(OH)2.
The solution for this third grade equation is
Now, let us calculate the moles in 1 L: