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GREYUIT [131]
11 months ago
5

12.if the amplitude of the waves in the previous question were doubles to 1 meter and the speed and wavelength remained the same

how many waves would strike you in 10 seconds?
Physics
1 answer:
QveST [7]11 months ago
8 0

By converting the 400 nm wavelength of violet light into meters we are get 4.0.10^-7.

What is wavelength?

Wavelength can be defined as the distance between two successive crests or throughs of a wave. It is measured in the direction of the wave. The wavelength of light defined as the distance between the two successive crests or throughs of the light wave.The wavelength of light is the distance between corresponding point in two adjacent light cycles and the frequency.

To know more about wavelength click -

brainly.com/question/10750459

#SPJ4

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6. A 2000 kg spacecraft is located 9.2x10 m from the center of the earth. The mass of the earth
Zina [86]

The answer is -i, trust me.

3 0
2 years ago
A 2.0-kg object moving with a velocity of 5.0 m/s in the positive x direction strikes and sticks to a 3.0-kg object moving with
Andrej [43]

Answer:

5.4 J.

Explanation:

Given,

mass of the object, m = 2 Kg

initial speed, u = 5 m/s

mass of another object,m' = 3 kg

initial speed of another orbit,u' = 2 m/s

KE lost after collusion = ?

Final velocity of the system

Using conservation of momentum

m u + m'u' = (m + m') V

2 x 5 + 3 x 2 = ( 2 + 3 )V

16 = 5 V

V = 3.2 m/s

Initial KE = \dfrac{1}{2}mu^2 + \dfrac{1}{2}m'u'^2

              = \dfrac{1}{2}\times 2\times 5^2 + \dfrac{1}{2}\times 3 \times 2^2

              = 31 J

Final KE = \dfrac{1}{2} (m+m')V^2 = \dfrac{1}{2}\times 5 \times 3.2^2 = 25.6 J

Loss in KE = 31 J - 25.6 J = 5.4 J.

4 0
3 years ago
2. When can you legally use your cell phone while
Juliette [100K]
Never is the correct answer
4 0
3 years ago
Read 2 more answers
How much work must be done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners
Natasha_Volkova [10]

Answer:

Potential\ Energy=Work \ Done=2.301*10^{-18} J

Work  done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners of an equilateral triangle) is 2.301*10^{-18} Joules

Explanation:

The potential energy is given by:

U=Q*V

where:

Q is the charge

V is the potential difference

Potential Difference=V=\frac{kq}{r}

So,

Potential\ Energy=\frac{Qkq}{r} \\Q=q\\Potential\ Energy=\frac{kq^2}{r}

Where:

k is Coulomb Constant=8.99*10^9 Nm^2/C^2

q is the charge on electron=-1.6*10^-19 C

r is the distance=3.0*10^{-10}m

For 3 Electrons Potential Energy or work Done is:

Potential\ Energy=3*\frac{kq^2}{r}

Potential\ Energy=3*\frac{(8.99*10^9)(-1.6*10^{-19})^2}{3*10^{-10}}\\Potential\ Energy=2.301*10^{-18} J

Work  done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners of an equilateral triangle) is 2.301*10^{-18} Joules

7 0
3 years ago
archer shoots his arrow towards a target at a distance of 90 m, and hits ‘bullseye’ . Calculate the acceleration and time taken
Cerrena [4.2K]
Answer:

Acceleration = 45m/s^2
Time = 2 s

Explanation:

6 0
3 years ago
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