Ask question

Ask question

All categories

1 year ago

5

12.if the amplitude of the waves in the previous question were doubles to 1 meter and the speed and wavelength remained the same

how many waves would strike you in 10 seconds?

1 answer:

QveST [7]1 year ago

8 0

By converting the 400 nm wavelength of violet light into meters we are get 4.0.10^-7.

What is wavelength?

Wavelength can be defined as the distance between two successive crests or throughs of a wave. It is measured in the direction of the wave. The wavelength of light defined as the distance between the two successive crests or throughs of the light wave.The wavelength of light is the distance between corresponding point in two adjacent light cycles and the frequency.

To know more about wavelength click -

brainly.com/question/10750459

#SPJ4

You might be interested in

A charge of +1 coulomb is place at the 0 cm mark of a meter stick. A charge of +4 coulombs is placed at the 100 cm mark of the s

UkoKoshka [18]

As per the question the charge of one coulomb is at 0 cm of the metre stick.the second charge of 4 coulomb is situated at at 100 cm of metre stick.

hence the separation distance between them is 100 cm.

now as per the question a proton is set up between them in such a way that the net force on it is zero

let the charge of proton is q coulomb let the proton is situated at distance of x cm from the charge 1 coulomb.hence it is situated at a distance of 100-x cm from the charge 4 coulomb.

the force exerted by 1 coulomb on proton is- $\frac{1}{4\pi\epsilon} \frac{1*q}{x^2}$

the force exerted by 4 coulomb on proton is- $\frac{1}{4\pi\epsilon} \frac{q*4}{[100-x]^2}$

as the net force is zero,hence-

$\frac{1}{4\pi\epsilon} \frac{1*q}{x^2}$ $=\frac{1}{4\pi\epsilon} \frac{4*q}{[100-x]^2}$

$=\frac{1}{x^2} =\frac{4}{[100-x]^2}$

$x^2=\frac{[100-x[^2}{4}[/tex[tex]x=\frac{100-x}{2}$

$3x=100$

$x=\frac{100}{3}$

$=33.33333$ cm [ans]

4 0

3 years ago

Read 2 more answers

What two quantities must stay the same in order for an object to have a constant velocity?

pentagon [3]

<span>Velocity is a vector and it has both speed and direction. It takes a force to change direction just as it does to change speed</span>. In order to have a constant velocity the object must maintain a constant direction and speed. Hope this answers the questions. Have a nice day.

8 0

3 years ago

Read 2 more answers

Doubly ionized lithium Li2+ (Z = 3) and triply ionized beryllium Be3+ (Z = 4) each emit a line spectrum. For a certain series of

EleoNora [17]

Answer:

tex]\lambda_{Be}[/tex] = 22.78 nm

Explanation:

Bohr's model for the hydrogen atom has been used by other atoms with a single electric charge by changing the number of charges by the charge of the new atom (atomic number)

$E_{n}$ = k e² / 2a₀ (1 /n²)

ao = h'² / k m e² h' = h/2πi

For another atom with a single electron in the last layer

a₀ ’= h’² / k m (Ze)²

a₀ ’= a₀ / Z²

Therefore, when replacing in the equation

$E_{n}$ = - Z² Eo/n²

E₀ = 13,606 eV

The transition occurs when the electron stops from one level to another

$E_{n}$ - $E_{m}$ = Z² E₀ (1 / n² - 1 / m²) = Z² ΔE

Let's relate this expression to the wavelength

c = λ f

E = h f

E = h c /λ

h c / λ = Z² ΔE

λ = 1 / Z² (hc / ΔE)

λ = 1 / Z² λ_hydrogen

Let's apply this last equation to our case

Lithium Z = 3

$E_{n}$ = - 9 Eo / n²

40.5 10-9 = 1/9 λ_hydrogen

Beryllium Z = 4

λ = 1/16 λ_hydrogen

Let's write our two equations is and solve

40.5 10-9 = 1/9 λ_hydrogen

tex]\lambda_{Be}[/tex] = 1/ 16 λ_hydrogen

40.5 10⁻⁹ = 1/9 (16 $\lambda_{Be}$ )

tex]\lambda_{Be}[/tex] = 40.5 9/16

tex]\lambda_{Be}[/tex] = 22.78 nm

6 0

3 years ago

A satellite orbits the earth a distance of 1.50 × 107 m above the planet's surface and takes 8.65 hours for each revolution abou

kupik [55]

Answer:

The acceleration of the satellite is $0.87 m/s^{2}$

Explanation:

The acceleration in a circular motion is defined as:

$a = \frac{v^{2}}{r}$ (1)

Where a is the centripetal acceleration, v the velocity and r is the radius.

The equation of the orbital velocity is defined as

$v = \frac{2 \pi r}{T}$ (2)

Where r is the radius and T is the period

For this particular case, the radius will be the sum of the high of the satellite ( $1.50x10^{7} m$ ) and the Earth radius ( $6.38x10^{6} m$ ) :

$r = 1.50x10^{7} m+6.38x10^{6}m$

$r = 21.38x10^{6}m$

Then, equation 2 can be used:

$T = 8.65 hrs \cdot \frac{3600 s}{1hrs}$ ⇒ $31140 s$

$v = \frac{2 \pi (21.38x10^{6}m)}{31140s}$

$v = 4313 m/s$

Finally equation 1 can be used:

$a = \frac{(4313m/s)^{2}}{21.38x10^{6}m}$

$a = 0.87 m/s^{2}$

Hence, the acceleration of the satellite is $0.87 m/s^{2}$

6 0

3 years ago

A ball is thrown vertically into the air and when it returns after an interval of 2 seconds, it is caught. Which one of the foll

baherus [9]

Answer:

Last statement option: "The acceleration after it leaves the hand is 10 m/s/s downwards."

Explanation:

At every instant of its motion, the ball is under the effects of the acceleration due to gravity (assumed to be 10 m/s^2). This is true at whatever altitude the ball is. The acceleration due to gravity is always pointing down (not up).

In the absence of air resistance, the motion is described kinematically by a parabola with the branches pointing down as a function of time (motion under constant acceleration), with the vertex indicating the maximum altitude the ball reaches. Both branches (representing motion upwards and downwards) are equidistant from the vertex, so the time going up equals the time coming down.

Therefore, the only statement option that is correct is the last one: "The acceleration after it leaves the hand is 10 m/s/s downwards."

8 0

4 years ago