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Akimi4 [234]
2 years ago
7

Suppose you want to operate an ideal refrigerator with a cold temperature of -10.0ºC , and you would like it to have a coefficie

nt of performance of 7. 00. What is the hot reservoir temperature for such a refrigerator? (answer in ºC)
Physics
1 answer:
Arlecino [84]2 years ago
7 0

Answer: temperature of the hot reservoir is 303.52K

Explanation:

Th=temperagture of hot reservoir

Tc=temperature of cold reservoir 263K

Eff=efficiency of the refrigerator

Cop=coefficient of performance

7

Eff=1/cop

Eff=1/7

Eff=0.142

Eff=1-263/th

0.142-1=-263/th

-0.858=-263/th

Th=303.52K

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The product of 14 and a cubed
olya-2409 [2.1K]

Answer:

14 × a^3

Explanation:

Product means multiplication

Cubed means to the power of 3

6 0
3 years ago
Read 2 more answers
A 1.2kg ball rolls forward with an acceleration of 1.11 m/s. What is the net force on the ball
grandymaker [24]

Answer:

1.332 N

Explanation:

Net Force = Mass x Acceleration
1.2 x 1.11 = 1.332 N

I'm so sorry if I'm wrong.

8 0
1 year ago
An object is positively charged if it has more what​
kkurt [141]

Answer:

An Object is positively charged if it has more Positive Electrons in that object

8 0
3 years ago
A lab cart with a mass of 15 kg is moving with constant velocity, v, along a straight horizontal track. A student drops a 2 kg m
lbvjy [14]

The equation 15v_{i} + 2*0 = (15 + 2)v_{f} (option 3) represents the horizontal momentum of a 15 kg lab cart moving with a constant velocity, v, and that continues moving after a 2 kg object is dropped into it.  

The horizontal momentum is given by:

p_{i} = p_{f}

m_{1}v_{1}_{i} + m_{2}v_{2}_{i} = m_{1}v_{1}_{f} + m_{2}v_{2}_{f}

Where:

  • m₁: is the mass of the lab cart = 15 kg
  • m₂: is the <em>mass </em>of the object dropped = 2 kg
  • v_{1}_{i}: is the initial velocity of the<em> lab cart </em>
  • v_{2}_{i}: is the <em>initial velocit</em>y of the <em>object </em>= 0 (it is dropped)
  • v_{1}_{f}: is the final velocity of the<em> lab cart </em>
  • v_{2}_{f}: is the <em>final velocity</em> of the <em>object </em>

Then, the horizontal momentum is:

15v_{1}_{i} + 2*0 = 15v_{1}_{f} + 2v_{2}_{f}

When the object is dropped into the lab cart, the final velocity of the lab cart and the object <u>will be the same</u>, so:

15v_{1}_{i} + 2*0 = v_{f}(15 + 2)

Therefore, the equation 15v_{i} + 2*0 = (15 + 2)v_{f} represents the horizontal momentum (option 3).

Learn more about linear momentum here:

  • brainly.com/question/2141713?referrer=searchResults
  • brainly.com/question/2400186?referrer=searchResults

I hope it helps you!            

4 0
2 years ago
Which artist of the northern European Renaissance, shown in this self-portrait, was also a block printer and engraver?
kicyunya [14]
It's very hard to see the self-portrait, so I can't identify him.
6 0
3 years ago
Read 2 more answers
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