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3 years ago

5

What is the difference between a graph of linear motion and a graph of harmonic motion?

1 answer:

fredd [130]3 years ago

5 0

Hope this helps :)

When describing linear motion, you need only one graph representing each of the three terms, while projectile motion requires a graph of the x and y axes. Graphs of simple harmonic motion are sine curves. Circular motion is different from other forms of motion because the speed of the object is constant.

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Which group of words do you think is an idiom?

Lady bird [3.3K]

Explanation:

a chip on your shoulder is an example

6 0

3 years ago

Read 2 more answers

Suppose that the average speed (vrms) of carbon dioxide molecules (molar mass 44.0 g/mol) in a flame is found to be 2.67 105 m/s

34kurt

Answer:

$T = 1.26 \times 10^8 K$

Explanation:

As we know that rms speed of ideal gas is given by the formula

$v_{rms} = \sqrt{\frac{3RT}{M}}$

here we know that

$v_{rms} = 2.67 \times 10^5 m/s$

molecular mass of gas is given as

$M = 44 g/mol = 0.044 kg/mol$

now from above formula we have

$2.67\times 10^5 = \sqrt{\frac{3(8.31)T}{0.044}}$

now we have

$T = 1.26 \times 10^8 K$

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4 years ago

A piano tuner stretches a steel piano wire with a tension of 1070 N . The wire is 0.400 m long and has a mass of 4.00 g . A. Wha

pychu [463]

A. 409 Hz

The fundamental frequency of a string is given by:

$f_1=\frac{1}{2L}\sqrt{\frac{T}{m/L}}$

where

L is the length of the wire

T is the tension in the wire

m is the mass of the wire

For the piano wire in this problem,

L = 0.400 m

T = 1070 N

m = 4.00 g = 0.004 kg

So the fundamental frequency is

$f_1=\frac{1}{2(0.400)}\sqrt{\frac{1070}{(0.004)/(0.400)}}=409 Hz$

B. 24

For this part, we need to analyze the different harmonics of the piano wire. The nth-harmonic of a string is given by

$f_n = nf_1$

where $f_1$ is the fundamental frequency.

Here in this case

$f_1 = 409 Hz$

A person is capable to hear frequencies up to

$f = 1.00 \cdot 10^4 Hz$

So the highest harmonics that can be heard by a human can be found as follows:

$f=nf_1\\n= \frac{f}{f_1}=\frac{1.00\cdot 10^4}{409}=24.5 \sim 24$

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4 years ago

Pls help me with these

Stells [14]

Answer:

number 1 is b number 2 is c number 3 is b

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3 years ago

7. Find the speed of a 22 kg mass with a momentum of 450 kgm/s. (Round

jeyben [28]

Answer:

i don't know if this is right but here,9900 kgm/s

Explanation:

calculator UwU

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4 years ago