Question

Can you show me how these are done ? show all work pleaseItem D

Answer 1

For the equation:

$_{}C_8H_{18}+O_2\to CO_2+H_2O$

We can balance it in many ways. It is better to balance it using C₈H₁₈ as reference.

Let's balance element by element.

For Carbon, C, we have, for now, 8 of them on the left side and 1 of them on the right side. For it to be balanced, we can multiply the compound of the right side by 8, like this:

$_{}C_8H_{18}+O_2\to8CO_2+H_2O$

Now, we have 8 carbons in each side, which is ok for now.

For hydrogen, H, we have 18 on the left side and 2 on the right side. To balance it, we can multiply the part on the right side by 9:

$_{}C_8H_{18}+O_2\to8CO_2+9H_2O$

Now, we have 18 in each side and we didn't change the C balance.

Next, for oxygen, O, we have 2 on the left side and 16 plus 9 on the right side, a total of 25.

If we change something on the right side, we will change the C or H balance, so let's chenge the left side.

We can only balance it by multiplying by 12.5, which is not normal, but that will do for now:

$C_8H_{18}+12.5O_2\to8CO_2+9H_2O_{}$

Now, everything is balanced, but we have a "12.5" coefficient. It is not wrong, but we can turn it into an integer to make it better. To do this, we can multiply it by 2, but to don't change the balance of the others, we mmultiply all coefficients by 2:

$2_{}C_8H_{18}+25O_2\to16CO_2+18H_2O$

Now, every element is balanced.