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vaieri [72.5K]
2 years ago
12

Select the true statement regarding the PSTN architecture.a. LATA are service providers that control LECsb. a COE is a tandem sw

itch that cannot connect directly to the subscriberc. an intraLATA call connects subscribers within the same LATAd. a CPE is a switching office that connects two or more tandem switches
Engineering
1 answer:
mrs_skeptik [129]2 years ago
8 0

The fact that an intra LATA call connects subscribers within the same LATA proves the PSTN architecture's correctness.

<h3>What does intra Lata mean?</h3>
  • Calls placed using the Local Toll Service (also known as IntraLATA Toll, Local Long Distance, or Regional Toll Service) are placed inside of the Local Access and Transport Area.
  • Calling a phone within the same LATA IntraLATA is the term for local phone service. An intraLATA call is one that travels from one LATA to another, either within the same state or between states.
  • The customer is charged for intra-LATA calls made to uninteresting neighboring towns. A LATA, which denotes local phone service, is made up of geographical areas.
  • Local Access and Transport Area, or LATA, is a three digit (5 in Florida) code that designates a particular geographic market where calls are forwarded.

To learn more about Transport Area, refer to:

brainly.com/question/28609231

#SPJ4

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Answer:

the lost work per kilogram of water for this everyday household happening = 0.413 kJ/kg

Explanation:

Given that:

Initial Temperature T_1 = 15°C

Initial Pressure P_1 = 5 atm

Final Pressure P_2 = 1 atm

Data obtain from steam tables of saturated water at  15°C are as follows:

Specific volume  v = 1.001 cm³/gm

The change in temperature = 2°C

Specific heat of water = 4.19 J/gm.K

volume expansivity β = 1.5 × 10⁻⁴ K⁻¹

The expression to determine the change in temperature can be given as :

\delta \ T = \frac{-V (1- \beta \ T}{C_p} * \delta \ P ( \frac{1}{9.87} \ \frac{J}{cm^3/atm})\delta \ T = \frac{-1.001 \frac{cm^3}{gm} (1- 1.5*10^{-4} \  K^{-1} )*2}{4.19 \ \frac{J}{gm.K}} *(5-1)atm ( \frac{1}{9.87} \ \frac{J}{cm^3/atm})

Δ T = 0.093 K

Now; we can calculate the lost work bt the formula:

W_{lost} = T_{surr} *S

where ;

T_{surr} is the temperature of the surrounding. = 20°C = (20+273.15)K =  293.15 K

From above the change in entropy is:

\delta \  S = C_p \  In (\frac{T+ \delta \ T }{T}) *  \beta V \delta P

\delta \  S = 4.19*  \  In (\frac{288.15+0.093 }{288.15}) -  1.5*10^{-4} * 1.001 (5-1)* (\frac{1}{9.87})

\delta \  S =1.408*10^{-3} \ J/gm.K

W_{lost} = T_{surr} *S

W_{lost} = 293.15* 1.408*10^{-3} \ J/gm.K

W_{lost} = 0.413 \  kJ/kg

Thus, the lost work per kilogram of water for this everyday household happening = 0.413 kJ/kg

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Answer:

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ΔQ = I* Δt (assuming that current remains constant during the charging process)

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Answer:

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Explanation:

Since, the position of a car is random.Therefore, number ways in which cars can line up is given as:

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Answer:

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Exit 2:-

Pressure P_{2} = 1 bar.

Solution:-

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