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3 years ago

What do you need for an object to fly?

Engineering

1 answer:

Kipish [7]3 years ago

7 0

Answer:

To fly, an aircraft needs something to push it in the opposite direction from gravity. The weight of an object controls how strong the push has to be.

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A rapid sand filter has a loading rate of 8.00 m/h, surface dimensions of 10 m ´ 8 m, an effective filtration rate of 7.70 m/h.

galben [10]

Answer:

Explanation:

given data

loading rate = 8.00 m/h

filtration rate = 7.70 m/h

dimensions = 10 m × 8 m

filter cycle duration = 52 h

time = 20 min

to find out

flow rate and volume of water is used for back washing plus rinsing the filter

solution

we consider here production efficiency is 96%

so here flow rate will be

flow rate = area × rate of filtration

flow rate = 10 × 8 × 7.7

flow rate = 616 m³/h

and

we know back washing generally 3 to 5 % of total volume of water per cycle so

volume of water is = 616 × 52

volume of water is 32032 m³

and

volume of water of back washing is = 4% of 32032

volume of water of back washing is 1281.2 m³

8 0

4 years ago

Technician A says the compressor is the dividing line of the refrigeration system, low- to high-side. Technician B says the expa

Fiesta28 [93]

The statements regarding the refrigeration system as expressed by the technicians are correct. Hence, the correct statement is Option c.

<h3>What is a refrigeration system?</h3>

Refrigeration systems are a crucial process in the industry and home applications as they carry out cooling or keep the room temperature at a preferred value.

The missing information in the question is:

A.technician A only

B.technician B only

C.both A and B

D.neither A or B

Hence, The statements regarding the refrigeration system as expressed by the technicians are correct. the correct statement is Option c.

Learn more about Refrigeration systems:

brainly.com/question/12135611

#SPJ1

7 0

2 years ago

Biomedical, electrical and civil engineering essay

ArbitrLikvidat [17]

Answer:

7th A good time for you arshpreet May God bless you live a long life of shapes in which class do read it and I am asking you are nagre andg my replying sooner than later this month to you arshpreet May God bless you live a long life of shapes in which class do read it and I am asking you are nagre andg my replying sooner than later this month to you arshpreet May God bless you live a long life of shapes in which class do read it and I am asking you are nagre andg my replying sooner than later this month to you arshpreet May God bless you live a long life of shapes in which class do read it and I am asking you are nagre andg my replying sooner than later this month to you arshpreet May God bless you live a long life of shapes in which class do read it and I am asking you are nagre andg my

3 0

3 years ago

A model of a submarine, 1:15 scale, is to be tested at 180 ft/s in a wind tunnel with standard sea-level air, while theprototype

ella [17]

Answer:

Explanation:

Given

scale i.e. $L_r=1:15$

Using Reynolds number similarity

$(Re)_m=(Re)_p$

$(\frac{Vl}{\nu })_m=(\frac{Vl}{\nu })_p$

Properties of air

$\nu _{air}=1.57\times 10^{-4} ft/s$

Properties of sea water

$\nu _{sea}=1.26\times 10^{-5} ft/s$

$\left ( \frac{V_ml_M}{\nu _m}\right )=\left ( \frac{V_pl_p}{\nu _p}\right )$

$V_p=V_m\left ( \frac{l_m}{l_p}\right )\left ( \frac{\nu _p}{\nu _m}\right )$

$V_p=180\times \frac{1}{15}\times \frac{1.26\times 10^{-5}}{1.57\times 10^{-4}}$

$V_p=0.963\ ft/s$

8 0

3 years ago

Explain the difference, on the basis of the test results, between the ultimate strength and the "true" stress at fracture.

gayaneshka [121]

Answer / Explanation:

On the basis of the test result, Ultimate strength which is mostly known as the ultimate tensile strength is the strength attached to the ability or capacity of a structural element or material used in the test to withstand elongation forces or pull force applied to it.

WHILE,

True stress at fracture can be classified as stress or load associated to the point where yielding or fracture occurred divided by the cross-sectional area at the yield point.

5 0

3 years ago