The turbocharger on a car applies a very similar principle to a piston engine. It uses the exhaust gas to drive a turbine. This spins an air compressor that pushes extra air (and oxygen) into the cylinders, allowing them to burn more fuel each second.
Answer:
C)185,500 KJ
Explanation:
Given that
Latent heat fusion = 333.23 KJ/kg
Latent heat vaporisation = 333.23 KJ/kg
Mass of ice = 100 kg
Mass of water = 40 kg
Mass of vapor=60 kg
Ice at 0°C ,first it will take latent heat of vaporisation and remain at constant temperature 0°C and it will convert in to water.After this water which at 0°C will take sensible heat and gets heat up to 100°C.After that at 100°C vapor will take heat as heat of vaporisation .
Sensible heat for water Q

For water

Q=4.178 x 40 x 100 KJ
Q=16,712 KJ
So total heat
Total heat =100 x 333.23+16,712 + 60 x 2257 KJ
Total heat =185,455 KJ
Approx Total heat = 185,500 KJ
So the answer C is correct.
Answer:
23 W/K
Explanation:
Entropy of water at 15°C is 224.5 J/kg/K.
Entropy of water at 15.2°C is approximately 227.4 J/kg/K (interpolated).
The increase in entropy is therefore:
227.4 J/kg/K − 224.5 J/kg/K = 2.9 J/kg/K.
So the rate of entropy generation is:
2.9 J/kg/K × 8 kg/s = 23.2 W/K
Rounded to two significant figures, the rate is 23 W/K.
Pretty sure it’s Cenozoic
Answer:
Check the explanation
Explanation:
Single Unit Truck ESAL = 43.38 + 5.16 = 48.54
Semi Unit Truck ESAL = 43.38+ 6.00+7.4 = 56.78
So total ESAL's during design life = (400*48.54 + 350*56.78)*365*10/18000 = (19416+19873)*3650= 3939
Kindly check the attached image
Here
Reliability = 95% = 0.95, therefore ZR = -1.645, S0 = 0.4, MR = 18
Delta PSI = 4.2-2.5= 1.7
Resilient Modulus = 18000 psi, So MR = 18
Assume SN = 3.0 for flexible pavements
There W18 calculates to 0.26807
So
log10 (3939) = 9.36*log10(SN+1) -.2/(.4+1094/(SN+1)5.19)) -6.01
Structural Number SN = a1*d1 + a2*d2 *m2 +a2*d3 *m3
= a1*d1 + a2*d2 +a2*d3